Describe how to perpare 75ml of 0.25M CuSO4 solution

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SUMMARY

To prepare 75 mL of a 0.25M CuSO4 solution, you need to calculate the required mass of cupric sulfate (CuSO4). The final desired volume is 0.075 liters, which corresponds to 0.01875 moles of CuSO4. Using the molar mass of CuSO4, which is approximately 159.61 g/mol, you will need to weigh out 3 grams of CuSO4 to achieve the desired concentration.

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  • Understanding of molarity and its calculations
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  • Familiarity with basic laboratory weighing techniques
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Homework Statement
Describe how to prepare 75mL of 0.25M ##CuSO_{4}## solution.
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The answer given to me by my teacher is 3 grams. I wasn't there when this was taught, and I have no formulas to use. I have searched for 30 minutes now and haven’t found any sources that gives a explanation. Any help that would lead me in the right direction would be great, thanks.
 
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Is the cupric sulfate from solid or from a given known concentration solution?

Final desired volume of 75 mL is same as 0.075 liters.
Look for formula weight of cupric sulfate, or compute this from data on Periodic Table.

Note, 0.075L*0.25(moles/L)=0.01875 moles of your salt.
 
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