Determine the equilibrium pH of aqueous solutions for the following strong acids

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Discussion Overview

The discussion focuses on determining the equilibrium pH of aqueous solutions for various strong acids and bases, specifically addressing the complexities involved with HSO4-, NaOH, and HNO3. The scope includes theoretical calculations and practical considerations in chemistry.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Homework-related

Main Points Raised

  • One participant requests assistance in calculating the pH or pOH for 257 mg/L of HSO4-, noting its amphiprotic nature.
  • Another participant suggests that H2SO4 is strong enough that HSO4- hydrolysis can be ignored, while providing a reference for further reading.
  • A participant critiques part (b) of the exercise, arguing that the concentration of NaOH at 10 nM is impractical in normal aqueous solutions due to buffering effects from carbon dioxide/bicarbonate.
  • One participant humorously notes that the question is a typical trick question, indicating a potential lack of seriousness in the exercise.

Areas of Agreement / Disagreement

Participants express differing views on the treatment of HSO4- and the practicality of the NaOH concentration, indicating that multiple competing perspectives remain without consensus.

Contextual Notes

There are unresolved assumptions regarding the behavior of HSO4- in solution and the impact of buffering on the pH of very dilute NaOH solutions.

tobyracine
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Determine the equilibrium pH of aqueous solutions for the following strong acids or bases: (a) 257mg/L of HSO4- ; (b) 10nM NaOH ; (c) 75ug/L of HNO3
 
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Look for their respective Ka values on net.
 
I kind of figured it out except for the first one, because HSO4- can become an acid or a base depending what it's mixed with so I don't know what to do, do I get the pH or the pOH? And how?
 
Thanks
 
Not totally relevant to the OP, but part (b) of this exercise is nonsensical in any practical terms. I bring this up because we are in the "Chemistry" forum rather than the "Chemistry Homework" forum.

The answer to a formal calculation to part (b) will only bear any relationship to reality if the concentration of carbon dioxide/bicarbonate in the water is much smaller than that of the hydroxyl -- say 1 nM or less. Any normal aqueous solution will be acting as a carbonate buffer for such low levels of hydroxyl, and I would like to know how anyone proposes to prepare a water sample that is accessible for normal laboratory work, but less than 1 nM in bicarbonate/carbon dioxide.
 
It is a typical trick question asked every year :smile:

And heck, you are right about homework... Moving the thread.

toby: please read forum rules.
 

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