1. The problem statement, all variables and given/known data So we did a lab in organic chemistry where we did a resolution experiment for enantiomers and in the separatory funnel we had sodium tartrate/tartaric acid left in the aqueous phase of the funnel. It asks why this compound is more soluble in high ph solutions as compared to low ph solution. 2. Relevant equations H2C4H4O6(aq) + H2O(l) = H30+(aq) + HC4H4O6-(aq) - disassociation reaction 3. The attempt at a solution The only think i could think of was in terms of le chatelier's principle where you dissociate less in a low ph solution due to excess H+ already present pushing equilibrium towards the reactants, while in a high ph solution the OH- will react with the H+ pushing equilibrium towards the products.