Determine when the velocity of the particle is zero

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SUMMARY

The discussion focuses on determining when the velocity of a particle becomes zero, given its initial position at X=0m, initial velocity of v=-6.0m/s, and an acceleration function of a(t) = 1.0 m/s² + (0.25 m/s³)t. Participants clarify that the area under the acceleration vs. time graph represents the change in velocity, and to find when the velocity equals zero, the area must equal 6 m/s, which corresponds to the initial velocity of -6.0 m/s increasing to 0 m/s.

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you_of_eh
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A particle has an initial position X=0m and an initial velocity v=-6.0m/s. Its acceleration is given by the function [1.0 m/s^2 + (0.25 m/s^3)t] where t is in seconds.

Plot the acceleration vs. time. From your plot, determine when the velocity of the particle is zero.

-ok so if when I plot this line, because acceleration is always positive, wouldn't the line just have a constant positive slope. I know you're supposed to find the area under the curve to get the velocity. But when the velocity equals 0? I don't get how I could find this from my
a vs t graph.
 
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you_of_eh said:
-ok so if when I plot this line, because acceleration is always positive, wouldn't the line just have a constant positive slope.
Yes.
I know you're supposed to find the area under the curve to get the velocity.

Actually, the area under the curve is the change in velocity, not the velocity itself; that's why the question gives you the initial velocity. So if you want v=0, delta v has to be 6 since -6+6=0. When is the area under the graph 6?
 

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