Determine whether the integer ## 1010908899 ## is divisible by....

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SUMMARY

The integer 1010908899 is confirmed to be divisible by 7, 11, and 13 through modular arithmetic. The calculation utilizes the relationship 7 × 11 × 13 = 1001 and the property 103 ≡ -1 (mod 1001). By breaking down 1010908899 into its components and applying modular reduction, the result shows that 1010908899 ≡ 0 (mod 1001), confirming its divisibility.

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Homework Statement
Without performing the divisions, determine whether the integer ## 1010908899 ## is divisible by ## 7, 11 ##, and ## 13 ##.
Relevant Equations
None.
Consider the integer ## 1010908899 ##.
Observe that ## 7\cdot 11\cdot 13=1001 ##.
Then ## 10^{3}\equiv -1\pmod {1001} ##.
Thus
\begin{align*}
&1010908899\equiv (1\cdot 10^{9}+10\cdot 10^{6}+908\cdot 10^{3}+899)\pmod {1001}\\
&\equiv (-1+10-908+899)\pmod {1001}\\
&\equiv 0\pmod {1001}.\\
\end{align*}
Therefore, the integer ## 1010908899 ## is divisible by ## 7, 11 ##, and ## 13 ##.
 
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Do you have a question somewhere? What do you need help with?
 
malawi_glenn said:
Do you have a question somewhere? What do you need help with?
The question is written in the homework statement. I just wanted someone to verify/confirm that my work is correct/accurate.
 
Math100 said:
The question is written in the homework statement.
Yeah I could see that, but what is your question to us?
Math100 said:
I just wanted someone to verify/confirm that my work is correct/accurate.
Ok.

Looks good to me.
You can include:
##10^9 \equiv_{1001} (10^3)^3 \equiv_{1001}(-1)^3 \equiv_{1001} -1##
##10^6 \equiv_{1001} (10^3)^2 \equiv_{1001}(-1)^2 \equiv_{1001} 1##
for the sake of completness.
 
Math100 said:
Homework Statement:: Without performing the divisions, determine whether the integer ## 1010908899 ## is divisible by ## 7, 11 ##, and ## 13 ##.
Relevant Equations:: None.

Consider the integer ## 1010908899 ##.
Observe that ## 7\cdot 11\cdot 13=1001 ##.
Then ## 10^{3}\equiv -1\pmod {1001} ##.
Thus
\begin{align*}
&1010908899\equiv (1\cdot 10^{9}+10\cdot 10^{6}+908\cdot 10^{3}+899)\pmod {1001}\\
&\equiv (-1+10-908+899)\pmod {1001}\\
&\equiv 0\pmod {1001}.\\
\end{align*}
Therefore, the integer ## 1010908899 ## is divisible by ## 7, 11 ##, and ## 13 ##.
This is correct, although I'm not sure whether you are supposed to solve it like that or apply the rules for divisibility by ##7,11,13.## IIRC then there are rules. But your solution is nicer.
 
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Maybe if you add ##1,001## to your original, it may become more clear
## 1,010, 908,899 +1,001=1,010,909,900-1,001,000,000=9,909,900##
 
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I was thinking about adding spacing ##1\,010\,908\,899## for "ocular ease" :)
 

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