Determining if Subset is a Subgroup by using Group Presentation

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SUMMARY

This discussion focuses on determining subgroup conditions within group presentations, specifically G=. The key points include that for a subset S to be a subgroup of G, the generators of S must satisfy the condition that for any elements a, b in S, the product ab^-1 must also be in S. Additionally, when considering two known subgroups A and B of G, a necessary and sufficient condition for A to be a subgroup is that every generator of A can be expressed as a word in the generators of B.

PREREQUISITES
  • Understanding of group presentations, specifically G=
  • Familiarity with subgroup criteria in group theory
  • Knowledge of generators and relations in algebraic structures
  • Basic concepts of group homomorphisms and word problems
NEXT STEPS
  • Study the properties of group presentations and their applications in algebra
  • Explore subgroup criteria in more depth, focusing on generating sets
  • Learn about the concept of words in groups and their implications for subgroup generation
  • Investigate the relationship between group homomorphisms and subgroup inclusion
USEFUL FOR

This discussion is beneficial for algebraists, mathematicians specializing in group theory, and students studying abstract algebra who are interested in subgroup properties and group presentations.

Bacle
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Hi, Algebraists:

Say I'm given a group's presentation G=<X|R>, with

X a finite set of generators, R the set of relations. A couple of questions, please:

i)If S is a subset of G what condition must the generators of

S satisfy for S to be a subgroup of G ? I know there is a condition

that if for any a,b in S, then S is a subgroup of G if ab^-1 is in S, but

I am tryng to work only with the generating set.

ii) If A,B are known to be subgroups of G; G as above: what

condition do I need on the generators of A,B respectively,

in order to tell if A is a subgroup of G? Is inclusion enough?

Thanks.
 
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I think a subset of a group which is generated by a set of generators is automatically a subgroup. I may be wrong though.
 
I got this one: a necessary and sufficient condition is that every generator of A can be
written as a word in B.
 

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