- #1
cookiemnstr510510
- 162
- 14
Hello all,
I have the "correct" answer from Chegg. However, I am not satisfied that I really understand.
Heres the problem:
Determine if the system is consistent. Do not completely solve the system.
2X1-4X4=-10
3X2+3X3=0
X3+4X4=-1
-3X1+2X2+3X3+X4=5
Here is my attempt:
I first write the system in the augmented matrix form, then reduce it to the "gaussian elimination" form (I think that's what my teacher called it).
##\begin{vmatrix}
2 & 0 & 0 & -4 & -10 \\
0 & 3 & 3 & 0 & 0\\
0 & 0 & 1 & 4 & -1\\
-3 & 2 & 3 & 1 & 5
\end{vmatrix}##
Now I multiply Row 1 by 1/2 ((R1)(1/2))
##\begin{vmatrix}
1 & 0 & 0 & -2 & -5 \\
0 & 3 & 3 & 0 & 0\\
0 & 0 & 1 & 4 & -1\\
-3 & 2 & 3 & 1 & 5
\end{vmatrix}##
Now I Add 3Row 1's to Row 4 (R4+3R1)
##\begin{vmatrix}
1 & 0 & 0 & -2 & -5 \\
0 & 3 & 3 & 0 & 0\\
0 & 0 & 1 & 4 & -1\\
0 & 2 & 3 & -5 & -10
\end{vmatrix}##
Now I multiply Row 2 by 1/3 ((R2)(1/3))
##\begin{vmatrix}
1 & 0 & 0 & -2 & -5 \\
0 & 1 & 1 & 0 & 0\\
0 & 0 & 1 & 4 & -1\\
0 & 2 & 3 & -5 & -10
\end{vmatrix}##
Now I subtract 2Row1 from Row 4 (R4-2R1)
##\begin{vmatrix}
1 & 0 & 0 & -2 & -5 \\
0 & 1 & 1 & 0 & 0\\
0 & 0 & 1 & 4 & -1\\
0 & 0 & 1 & -5 & -10
\end{vmatrix}##
Now I subtract Row 3 from Row 4 (R4-R3)
##\begin{vmatrix}
1 & 0 & 0 & -2 & -5 \\
0 & 1 & 1 & 0 & 0\\
0 & 0 & 1 & 4 & -1\\
0 & 0 & 0 & -9 & -9
\end{vmatrix}##
Now I multiply Row 4 by (-1/9) ((R4)(-1/9))
##\begin{vmatrix}
1 & 0 & 0 & -2 & -5 \\
0 & 1 & 1 & 0 & 0\\
0 & 0 & 1 & 4 & -1\\
0 & 0 & 0 & 1 & 1
\end{vmatrix}##
So at this point we see that in Row 4 that X4=1 and this means it is consistent?!
I don't see how this means it is consistent.
Thanks!
I have the "correct" answer from Chegg. However, I am not satisfied that I really understand.
Heres the problem:
Determine if the system is consistent. Do not completely solve the system.
2X1-4X4=-10
3X2+3X3=0
X3+4X4=-1
-3X1+2X2+3X3+X4=5
Here is my attempt:
I first write the system in the augmented matrix form, then reduce it to the "gaussian elimination" form (I think that's what my teacher called it).
##\begin{vmatrix}
2 & 0 & 0 & -4 & -10 \\
0 & 3 & 3 & 0 & 0\\
0 & 0 & 1 & 4 & -1\\
-3 & 2 & 3 & 1 & 5
\end{vmatrix}##
Now I multiply Row 1 by 1/2 ((R1)(1/2))
##\begin{vmatrix}
1 & 0 & 0 & -2 & -5 \\
0 & 3 & 3 & 0 & 0\\
0 & 0 & 1 & 4 & -1\\
-3 & 2 & 3 & 1 & 5
\end{vmatrix}##
Now I Add 3Row 1's to Row 4 (R4+3R1)
##\begin{vmatrix}
1 & 0 & 0 & -2 & -5 \\
0 & 3 & 3 & 0 & 0\\
0 & 0 & 1 & 4 & -1\\
0 & 2 & 3 & -5 & -10
\end{vmatrix}##
Now I multiply Row 2 by 1/3 ((R2)(1/3))
##\begin{vmatrix}
1 & 0 & 0 & -2 & -5 \\
0 & 1 & 1 & 0 & 0\\
0 & 0 & 1 & 4 & -1\\
0 & 2 & 3 & -5 & -10
\end{vmatrix}##
Now I subtract 2Row1 from Row 4 (R4-2R1)
##\begin{vmatrix}
1 & 0 & 0 & -2 & -5 \\
0 & 1 & 1 & 0 & 0\\
0 & 0 & 1 & 4 & -1\\
0 & 0 & 1 & -5 & -10
\end{vmatrix}##
Now I subtract Row 3 from Row 4 (R4-R3)
##\begin{vmatrix}
1 & 0 & 0 & -2 & -5 \\
0 & 1 & 1 & 0 & 0\\
0 & 0 & 1 & 4 & -1\\
0 & 0 & 0 & -9 & -9
\end{vmatrix}##
Now I multiply Row 4 by (-1/9) ((R4)(-1/9))
##\begin{vmatrix}
1 & 0 & 0 & -2 & -5 \\
0 & 1 & 1 & 0 & 0\\
0 & 0 & 1 & 4 & -1\\
0 & 0 & 0 & 1 & 1
\end{vmatrix}##
So at this point we see that in Row 4 that X4=1 and this means it is consistent?!
I don't see how this means it is consistent.
Thanks!