Determining pH of Solution: 2 Acid Mix with HCl and CH3COOH

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Discussion Overview

The discussion revolves around determining the pH of a solution formed by mixing two acids: hydrochloric acid (HCl) and acetic acid (CH3COOH). Participants explore the implications of the concentrations of each acid and how they affect the overall pH of the resulting solution, addressing both theoretical and practical aspects of pH calculation in mixed acid solutions.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant questions how to determine the pH of a solution with two acids and provides specific concentrations for HCl and CH3COOH.
  • Another participant notes the difficulty in calculating the pH of such a solution and prompts consideration of the pH of HCl without acetic acid.
  • A participant suggests that the contribution of H+ from HCl is negligible compared to that from water, proposing a pH of 7.00 for the first solution and indicating that the initial H+ concentration from HCl may not significantly affect the equilibrium of acetic acid.
  • There is confusion expressed about the total volume of the solution, with a participant questioning why the final volume is stated as 50 mL instead of 60 mL.
  • Another participant confirms the previous claims about pH and volume, but there is still uncertainty regarding the treatment of HCl in calculations.
  • One participant explicitly asks if HCl can be neglected due to its negligible concentration, to which another participant agrees.

Areas of Agreement / Disagreement

Participants express uncertainty about the treatment of HCl in the calculations, with some suggesting it can be neglected while others question this approach. The discussion remains unresolved regarding the implications of neglecting HCl and the final pH determination.

Contextual Notes

There are limitations regarding the assumptions made about the contributions of H+ ions from HCl and the implications of the stated volumes in the problem. The discussion does not resolve these issues.

firyace
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Hi, I got a problem with something regarding to chemistry. How can you determine the pH of a solution with two Acids?

The question says that A 50.00 mL aqueous solution is made by mixing the following two solutions:

10.00mL 1x10^-9M HCl

50.00mL 1*10^-4 M CH3COOH (Ka= 1.8*10^-5)

a) What is the Cl^- in the 50.00mL solution?
b)What is the pH in the 50mL solution?
c) What is the [CH3COOH] in the 50mL solution?


thanks!
 
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In general it is difficult to calculate pH of such solution, but here... Look at the concentration of hydrochloric acid. What pH does it have without acetic acid?
 
This is my guess (please take this lightly):

The contribution of H+ from the HCl will be negligible compared to the contribution from water, which would make the pH of the first solution 7.00. To figure out the pH of the other solution, just do a regular equilibrium problem using the acetic acid. The initial H+ concentration will be 1.0 x 10^-9, but I don't think it will matter because it's negligible.

Note: I'm confused as to why the question says that a 50 mL solution is formed instead of a 60 mL solution...
 
You are correct on both accounts - pH and volume ;)
 
So now I am confused, do I just neglect the HCl totally because that the concentration is neglegible?

'm confused as to why the question says that a 50 mL solution is formed instead of a 60 mL solution...
Yesterday 06:30 AM
:bugeye: that is what it said for the question.
 
firyace said:
So now I am confused, do I just neglect the HCl totally because that the concentration is neglegible?

Yes.
 

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