Determining Quadratic Function for a Graph

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Sharpy1
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Hmm I'm having issues with an optional problem for some review for a quiz later tonight.

Determine the Quadratic Function for the Graph
the points labeled are X intercepts =(-3,0) (5,0); Y-Intercept = (0,-30), Local Min/Vertex = (1,-32)
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It's the parabola looking problem at the bottom right, sorry I wasn't able to snap a good picture of it.

This is part of some optional review and I have a few hours before the quiz so any help would be appreciated. I'm honestly not even sure where to being other than putting "-32" at the end of the equation as the interpretation of the minimum point.
 

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A parabola with vertex at $(x_0,y_0)$ has equation $y(x)=a(x-x_0)^2+y_0$ for some $a$. So, here the formula is $y(x)=a(x-1)^2-32$. Find $a$ from the fact that $y(5)=0$ or from $y(0)=-30$.