- #1
Monoxdifly
MHB
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A quadratic function \(\displaystyle f(x)=x^2+2px+p\) has the minimum value of –p with \(\displaystyle p\neq0\). If the curve's symmetrical axis is x = a, then a – f(a) = ...
A. –6
B. –4
C. 4
D. 6
E. 8
Because the curve's symmetrical axis is x = a, then:
\(\displaystyle -\frac{2p}{2(1)}=a\)
–p = a
a – f(a) = –p + (–p) = 0
I got zero. Is there anything I did wrong?
A. –6
B. –4
C. 4
D. 6
E. 8
Because the curve's symmetrical axis is x = a, then:
\(\displaystyle -\frac{2p}{2(1)}=a\)
–p = a
a – f(a) = –p + (–p) = 0
I got zero. Is there anything I did wrong?