Determining the empirical formula of Magnesium Oxide

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SUMMARY

The empirical formula of Magnesium Oxide (MgO) is established as a 1:1 ratio of magnesium to oxygen. If magnesium oxide smoke escapes during the experiment, the Mg:O ratio will decrease due to a loss of magnesium, which is a reactant in the formation of MgO. Calculations should focus on the initial moles of magnesium and oxygen compared to the remaining amounts after the loss of magnesium oxide. This understanding is crucial for accurately determining the empirical formula in experimental conditions.

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Homework Statement


I already did the experiment but I'm trying to answer a question which asks"

Suppose that you allowed some magnesium oxide smoke to escape during the experiment. How would the Mg:O ratio have been affected? Would the ratio have decreased, increased or stayed the same? Explaine using calculations.


Homework Equations


I already know the empirical formula is MgO

The Attempt at a Solution


I think it will stay the same because you can't really reduce the ratio any furthur but I don't know how to show it using calculations. please help and thanks.
 
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bubbles1234 said:

Homework Statement


I already did the experiment but I'm trying to answer a question which asks"

Suppose that you allowed some magnesium oxide smoke to escape during the experiment. How would the Mg:O ratio have been affected? Would the ratio have decreased, increased or stayed the same? Explaine using calculations.


Homework Equations


I already know the empirical formula is MgO

The Attempt at a Solution


I think it will stay the same because you can't really reduce the ratio any furthur but I don't know how to show it using calculations. please help and thanks.

You are probably right however keep in mind that I do not know the context of the experiment.
 

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