Did I solve this diff eq substition problem properly?

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The forum discussion centers on solving the differential equation xy' = yln(xy) using substitution. The user successfully applies the substitution v = ln(xy), leading to the integral ∫(dv/(v+1)) = ∫(dx/x). The solution results in ln(v+1) = ln(x) + C, which simplifies to v + 1 = Cx, ultimately yielding ln(xy) + 1 = Cx. The user suggests verifying the solution by solving for y and checking against the original equation.

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[itex]xy'=yln(xy)[/itex]
[itex]xdy=yln(xy)dx[/itex]
[itex]\frac{dy}{y}[/itex]=[itex]\frac{ln(xy)dx}{x}[/itex]

Substitution:

[itex]v=ln(xy)[/itex]
[itex]dv[/itex] = [itex]\frac{dy}{y}[/itex]-[itex]\frac{dx}{x}[/itex]
[itex]dv[/itex]-[itex]\frac{dx}{x}[/itex]=[itex]\frac{vdx}{x}[/itex]

∫[itex]\frac{dv}{v+1}[/itex]=∫[itex]\frac{dx}{x}[/itex]

[itex]ln(v+1)=ln x + C[/itex]

v+1 = Cx
ln(xy) +1 = Cx

Would that basically be the complete answer?
 
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It might be interesting to solve this last equation for y=... and verify the answer with the initial equation.
 

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