MHB Differential Equations by separation of variables

LAK
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Can someone please help me to calculate the following using separation of variables:

dy/dx = x*(1 - y^2)^(1/2)

to that the solution is in the form:

y =
 
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I have moved both your threads here to the Differential Equations subforum as this is a better fit for them.

What do you get when you separate the variables, before integrating?
 
LAK said:
Can someone please help me to calculate the following using separation of variables:

dy/dx = x*(1 - y^2)^(1/2)

to that the solution is in the form:

y =

For starters:

$\displaystyle \begin{align*} \frac{1}{\sqrt{1 - y^2}} \, \frac{dy}{dx} = x \end{align*}$

and now you can integrate both side w.r.t. x :)
 
Thread 'Direction Fields and Isoclines'
I sketched the isoclines for $$ m=-1,0,1,2 $$. Since both $$ \frac{dy}{dx} $$ and $$ D_{y} \frac{dy}{dx} $$ are continuous on the square region R defined by $$ -4\leq x \leq 4, -4 \leq y \leq 4 $$ the existence and uniqueness theorem guarantees that if we pick a point in the interior that lies on an isocline there will be a unique differentiable function (solution) passing through that point. I understand that a solution exists but I unsure how to actually sketch it. For example, consider a...
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