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Getting stuck on this equation.

e^(-x) / ln(x)

Solving it by quotient rule, however answer has extra x in numerator.

using the dy/dx = (v(du/dx)-u(dv/dx))/v^2

dy/dx = (ln(x)*-e^(-x) - (-e^(-x)*1/x)/ln(x)^2

Answer = (-e^(-x) (x ln(x)-1))/x(ln(x))^2

Would appreciate help with breaking this down. Cheers

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# Differentiation of e^(-x) / ln(x)

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