Difficult maths problem - requires some thought

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The discussion focuses on determining the time after 8 o'clock when the hour and minute hands of a clock are exactly 180 degrees apart. The key angles are defined as m for the minute hand and h for the hour hand, with the equation h - m = 180 being central to solving the problem. It is noted that the hands are opposite each other 11 times in a 12-hour period, with a specific example given at 6 o'clock. Participants are encouraged to share their attempts for guidance.

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After the hour hand has passed 8 on your watch, when will the minute hand and the hour hand be pointing in exactly opposite directions?

I did initially try formulating equations based on the change in the angle of the hour hand after x minutes, but it doesn't seem to be taking me anywhere.

I don't even know where to start on this question, any pointers in what direction I should head would be appreciated.
 
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When the time is x minutes past the hour, what is the angle (in degrees) between the minute hand and 12 o'clock (measured clockwise)? Call this angle m. (Note that x need not be a whole number.)

When the time is 8 o'clock and x minutes, what is the angle (in degrees) between the hour hand and 12 o'clock (measured clockwise)? Call this angle h.

For what value of x do we have h-m=180?
 
The easy way is to notice the hour and minute hand are pointing in opposite directions at 6 o'clock, and every 12 hours there are exactly 11 times they are pointing in opposite directions. Now you can figure out the times. But you can also do it with rates. Post your attempt and someone will probably show you where you went wrong.
 

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