DeltaH of Diluting 24% NaOH to 2% in H2O

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SUMMARY

The discussion focuses on calculating the enthalpy change (DeltaH) when diluting a 24% sodium hydroxide (NaOH) solution to 2% by adding water. Participants reference a specific table for dilution heats and highlight discrepancies in methods for determining final temperature and enthalpy of dilution. The correct procedure involves three steps: considering the initial composition, the amount of water added, and the desired final composition. The conversation emphasizes the importance of using accurate methods and resources for calculating thermodynamic properties in chemical solutions.

PREREQUISITES
  • Understanding of thermodynamics, specifically enthalpy changes
  • Familiarity with sodium hydroxide (NaOH) properties and behavior in solution
  • Knowledge of dilution principles and calculations
  • Ability to interpret thermodynamic tables and graphs
NEXT STEPS
  • Research the enthalpy of dilution for various concentrations of sodium hydroxide
  • Learn how to use thermodynamic tables for calculating heat changes in chemical reactions
  • Study the method for calculating final temperatures in solution mixing
  • Explore the differences in enthalpy curves for different concentrations of NaOH solutions
USEFUL FOR

Chemists, chemical engineers, and students studying thermodynamics or solution chemistry will benefit from this discussion, particularly those involved in calculating heat changes during chemical dilutions.

katchum
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Hello

I know that dissolving pure NaOH in water will generate heat. But what happens when you dilute a 24% NAOH solution with water till 2%?

Example: What is the DeltaH for 100 ml 24% NaOH solution + 50 ml H2O?

Thanks
 
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Dilution heats are tabelarized.
 
That's right.

I found this nice table: http://www.pioneercompanies.com/customers/tech/data/naoh/ENTHALPY.pdf

You just draw a line between your solutions and you can see the final temperature.
 
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What's wrong with my method? I was asked to calculate the final temperature of the solution.

Additionally, this is the method described by the company itself:

http://www.pioneercompanies.com/customers/tech/data/naoh/DILUTION%20OF%20SODIUM%20HYDROXIDE%20SOLUTIONS.pdf

What I don't understand is, the two curves aren't the same, or am I not seeing right? There is a flattening of the curve close to 0 % for low temperatures.

The minima aren't the same either.

(as for the enthalpy of dilution, I would substract the initial and end enthalpies with each other and that's the answer)
 
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Your method is two steps , the actual method consists of three steps and three independent variables for a dilution ; first composition , water , and the desired composition.
 

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