Dimensional Analysis involving power

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Homework Help Overview

The problem involves dimensional analysis related to the power required by a helicopter when hovering, focusing on the relationship between power, vertical thrust, length of the blades, and air density. The original poster seeks to establish an equation connecting these variables and to determine how the power requirement changes when the helicopter takes on a load that doubles its weight.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to use dimensional analysis to derive an equation for power based on thrust, density, and length. Some participants question the validity of the derived exponents and suggest re-evaluating the equations. Others propose substituting the force values to explore the impact of doubling the weight on power requirements.

Discussion Status

Participants are actively engaging with the original poster's attempts, providing feedback on the dimensional analysis and suggesting corrections. There is a recognition of potential errors in the calculations, and some participants express uncertainty about the implications of the derived relationships. The discussion is ongoing, with various interpretations being explored.

Contextual Notes

There are indications of confusion regarding the relationships between the variables, particularly concerning the implications of the exponent values derived from the dimensional analysis. The original poster has acknowledged mistakes and is working to clarify the equations.

d97

Homework Statement


The power required by a helicopter when hovering depends only upon the vertical thrust (a force) F provided by the blades, their length l, and the mass density of air, ρ. Establish an equation that relates the helicopters power requirement to these three quantities. By what factor is the power requirement increased such that the helicopter can maintain a constant altitude when it takes on a load that doubles its weight?

Homework Equations


[Power]= M*L^2*T^-3, [Density]=[M*L^-3], Length= [L], [Force]= M*L*T^-2
Power= F^a*p^b*L^c[/B]

The Attempt at a Solution


I've done the first part of the question through using dimensional analysis: M*L^2*T^-3=[M*L*T^-2]^a*[M*L^-3]^b*[L]^c. I came up with these equations to get the powers for the RHS: a+b=a, a-3b+c=2 and a=-1. This gave me a=-1, b=2, c=9 this means that Power= F^-1*p^2*L^9, I think that's right?
I'm just unsure on how to do the second part of the question where its asking for a factor of power?
Any help would be much appreciated thank you. [/B]
 
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Suppose the initial force required to hover is denoted by F1. Then the force required to hover with twice the weight is 2F1. Put that into your equations and see what happens to the 2 multiplier.

PS. I didn't try to follow your equations, but it looks like a = -1 means that more lift force requires less power. That seems wrong to me.
 
Check again your equations. If a+b = a, then b = 0. Also the equation from the exponents of T doesn't look right.
 
kuruman said:
Check again your equations. If a+b = a, then b = 0. Also the equation from the exponents of T doesn't look right.
Sorry my bad a+b=1, I miss typed
 
FactChecker said:
Suppose the initial force required to hover is denoted by F1. Then the force required to hover with twice the weight is 2F1. Put that into your equations and see what happens to the 2 multiplier.

PS. I didn't try to follow your equations, but it looks like a = -1 means that more lift force requires less power. That seems wrong to me.
Oh ok thank you, yeah I think a=-1 is wrong I looked at it again and I think a=3/2 instead. I'll work it out again and I'll put that 2 multiplier into my equation once I've corrected my mistakes.
 
FactChecker said:
Suppose the initial force required to hover is denoted by F1. Then the force required to hover with twice the weight is 2F1. Put that into your equations and see what happens to the 2 multiplier.

PS. I didn't try to follow your equations, but it looks like a = -1 means that more lift force requires less power. That seems wrong to me.
I've sorted my mistakes out and I got power= F^3/2*p^-1/2*L^-1, I hope that is right? And put the 2 multiplier into my equation and the power increases by a factor of 2.83, I think that's right?
 
d97 said:
I've sorted my mistakes out and I got power= F^3/2*p^-1/2*L^-1, I hope that is right? And put the 2 multiplier into my equation and the power increases by a factor of 2.83, I think that's right?
Sorry. I'm afraid that I don't have the background to check it. I'll have to leave this for people who know the subject matter better than I do.
 
d97 said:
power= F^3/2*p^-1/2*L^-1
It's right.
 
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