Discover the Number of 8 Letter Words with 3 Vowels and Non-Repeating Consonants

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Homework Help Overview

The discussion revolves around determining the number of 8-letter words that can be formed with 3 vowels and non-repeating consonants. Participants are exploring the implications of order and repetition in their calculations.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to formulate the problem using combinations and permutations, questioning the need to factor in order and the uniqueness of letters. There is discussion about whether to use factorials or combinations in their calculations.

Discussion Status

The discussion is active with various interpretations being explored. Some participants are suggesting different approaches to integrate vowels with consonants, while others are questioning the assumptions about repetition and order in their calculations.

Contextual Notes

There is a noted confusion regarding the distinction between vowels and consonants, particularly the total number of consonants available for selection. Participants are also considering the implications of their choices on the final count of unique words.

Miike012
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How many 8 letter words have 3 vowels constants do not repeat.

Is it
5^3*26*25*24*23*22 ?
 
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Miike012 said:
How many 8 letter words have 3 vowels constants do not repeat.

Is it
5^3*26*25*24*23*22 ?

Don't you have to also factor in order too:

act vs cat vs some nonsense words like tca, cta ...

cafe vs face
 
Another question how do I know when to use the combination equation or permutation equation?
For instance given the example which is posted above are the following strings the same?

A E I M N P Q R
and
E A I M N P Q R
They both contain the same three vowels and the only thing I changed was the placement of the first and second terms
 
jedishrfu said:
Don't you have to also factor in order too:

act vs cat vs some nonsense words like tca, cta ...

cafe vs face

so I should add 8! ?
 
jedishrfu said:
Don't you have to also factor in order too:

act vs cat vs some nonsense words like tca, cta ...

cafe vs face

I'm not sure that would work, for instance


A1 B A2
and
A2 B A1

are the same.

I almost feel like I should add (8 choose 3) instead of 8!
 
Miike012 said:
I'm not sure that would work, for instance


A1 B A2
and
A2 B A1

are the same.

I almost feel like I should add (8 choose 3) instead of 8!

I think your consonants are unique but your vowels might repeat so you'd also have to factor that in too.
 
Miike012 said:
so I should add 8! ?

You mean multiply by 8!?
No, your original formula already has some ordering in it.
For the vowels you have 53, so you've already counted all vowel orders.
Similarly, for the consonants, you used 26P5, not 26C5, so you have those ordered.
All that you are missing is integrating the vowels with the consonants. How many ways are there of doing that?
 
Remember that the vowels are part of the 26 letters. There are only 21 consonants.
 
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vela said:
Remember that the vowels are part of the 26 letters. There are only 21 consonants.

I missed that, thanks.
 
  • #10
vela said:
Remember that the vowels are part of the 26 letters. There are only 21 consonants.

How true :redface:
 

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