Discover the Solution to the World's Hardest Easy Problem on Thinkzone.wlonk.com

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Discussion Overview

The discussion revolves around a mathematical problem involving angles in a triangle, specifically focusing on the equation x + y = 130, where x and y are angles. Participants explore various approaches to solve this problem, which is framed as a diophantine equation, and discuss geometric strategies related to the problem.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • Some participants identify the equation x + y = 130 and note that x and y are positive integers, with y being greater than 90 degrees.
  • Others suggest possible angle pairs, such as x = 20° and y = 110°, or x = 30° and y = 100°.
  • One participant expresses frustration with the problem-solving process and seeks guidance on how to approach it, indicating a lack of patience for constructing the necessary geometric figures.
  • Another participant emphasizes the importance of attempting the problem independently before seeking help, suggesting that showing effort is crucial in the forum context.
  • Some participants discuss the strategy of drawing triangles to scale, with one noting that they find it challenging to visualize geometry mentally.
  • A later reply mentions the possibility of proving triangles similar to find the value of x.

Areas of Agreement / Disagreement

Participants express a range of views on how to approach the problem, with no consensus on a definitive solution. Some agree on the need for geometric construction, while others question the effectiveness of certain strategies.

Contextual Notes

Participants mention the diophantine nature of the equation and the angle sum property, but there are unresolved mathematical steps and assumptions regarding the angles involved.

Who May Find This Useful

This discussion may be of interest to students preparing for mathematics competitions, particularly those focused on geometry and problem-solving strategies.

namanjain
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I haven't the solution, I get the equation x + y = 130, where x and y are angles. If [itex]x, y \in Z^+[/itex]
This is a diophantine equation. We know: x, y > 0. y > x. And y is greater than 90 degrees.
the most probable angles:
[itex]x=20^o\,\, ,y=110^o[/itex]
or
[itex]x=30^o\,\, ,y=100^o[/itex]
 
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I tried a couple of things but didn't solve it yet , but there's probably a way to build your way up to the x angle using the tricks in my sketch (just don't have the patience to construct the triangles properly and doing it now):
 

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Simple geometry is all that is required.

Why can't you do this for yourself? Don't give up so easy.
 
janhaa said:
diophantine equation
wazz it,
i tried it hard that's why asking askin solution,
well i need an approach
i asked it to one of my faculty at coaching and he straightaway said it's wrong so i needed to check
 
janhaa said:
I haven't the solution, I get the equation x + y = 130, where x and y are angles. If [itex]x, y \in Z^+[/itex]
This is a diophantine equation. We know: x, y > 0. y > x. And y is greater than 90 degrees.
the most probable angles:
[itex]x=20^o\,\, ,y=110^o[/itex]
or
[itex]x=30^o\,\, ,y=100^o[/itex]

reenmachine said:
I tried a couple of things but didn't solve it yet , but there's probably a way to build your way up to the x angle using the tricks in my sketch (just don't have the patience to construct the triangles properly and doing it now):
whatss y in equation
x+y= 130

reenmachine i agree myself i even not have patience and doing it (doing angle sum property question) , thanks for tip of parallel lines but what benefit it does
 
namanjain said:
reenmachine i agree myself i even not have patience and doing it (doing angle sum property question) , thanks for tip of parallel lines but what benefit it does

I don't know since I didn't solve it.It was just a suggestion of strategy to attack the problem , maybe it's a dead end , but the parallel lines will at least allow you to chase more angles , whether or not they end up being useful to find angle x.

If you don't have the patience to try it , I suggest you do not ask others to do it for you as it's not recommended on the forum to ask for answers without showing that you tried hard before hand.I'm not a moderator , just friendly advice.Also , saying that you tried hard is not showing that you tried hard.
 
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till here i ve done (in attchment)
one of image is inverted
so i did the mirror image from webcam toy
 

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You should draw the triangles/angles to scale if you want to try that strategy.

It should look like the picture below
 

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  • #10
kingo1979 said:
from the original figure below, y seems equal angle bde

http://thinkzone.wlonk.com/mathfun/triangle.htm
=====
where x + y + 50 = 180
however i got that but i also meant that diophtine (whatever is name) equation

well where is it taught
 
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  • #11
reenmachine said:
you should draw the triangles/angles to scale if you want to try that strategy.

It should look like the picture below

does that help, because doing any of olympiads we were never told to draw to scale and i was always of kind to do geometry of this kind mentally so it's quite difficult for me
though i think i'll print that page
 
  • #12
Uff! After long work with a correct precise figure i bored and saw solution on one of other web pages

is it bad of me not getting it (i'm 15 yrs and preparing rmo and iit)
 
  • #13
namanjain said:
does that help, because doing any of olympiads we were never told to draw to scale and i was always of kind to do geometry of this kind mentally so it's quite difficult for me
though i think i'll print that page

I don't know , you should listen to your teachers before you listen to me that's for sure :-p

You should also listen to mentors here as they are qualified to help you.
 
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  • #14
Might try to prove both of these triangles (or another pair of triangles) are similar to prove x = 20 :
 

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