- #1
mnb96
- 715
- 5
Hello,
If we are given a gaussian function which is continuous in x we know that:
[tex]\int_{-\infty}^{+\infty}e^{-x^2}dx=\sqrt{\pi}[/tex]
What if the gaussian function is discrete in x?
What is the result of
[tex]\sum_{x=-\infty}^{+\infty}e^{-x^2} = \\?[/tex]
where [itex]x\in \mathbb{Z}[/itex]
If we are given a gaussian function which is continuous in x we know that:
[tex]\int_{-\infty}^{+\infty}e^{-x^2}dx=\sqrt{\pi}[/tex]
What if the gaussian function is discrete in x?
What is the result of
[tex]\sum_{x=-\infty}^{+\infty}e^{-x^2} = \\?[/tex]
where [itex]x\in \mathbb{Z}[/itex]
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