Distance Needed to Reach Terminal Velocity

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SUMMARY

The discussion focuses on calculating the minimum distance required to reach terminal velocity for an object with a mass of 0.5 kg and a drag coefficient of 0.6, experiencing quadratic air resistance. The gravitational force is set at 9.81 m/s², and the initial velocity is 0 m/s. The key equation derived is mg = k*v², which equates gravitational force to drag force at terminal velocity. The integration of the net force equation m*a(net) = mg - kv² is essential for determining the distance to terminal velocity.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with quadratic drag equations
  • Basic knowledge of calculus for integration
  • Proficiency in Python programming for simulations
NEXT STEPS
  • Study the integration of differential equations in physics
  • Learn about terminal velocity calculations in fluid dynamics
  • Explore Python libraries for numerical integration, such as SciPy
  • Research the effects of varying drag coefficients on falling objects
USEFUL FOR

Students in physics and engineering courses, Python programmers working on simulations, and anyone interested in understanding the dynamics of falling objects under air resistance.

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Homework Statement



I am completing a homework assignment that involves a python program for air resistance. One of the questions in the assignment asks us to find the minimum distance needed to reach terminal velocity. The air resistance is quadratic. The mass of the object is .5kg and its drag coefficient is .6
The gravity is normal Earth gravity, 9.81m/s^2, and the initial velocity is 0m/s.

Homework Equations


The force of air resistance=-k*v^2


The Attempt at a Solution


I think the solution involves integrating a velocity function from time 0 to 5*time constant. However, I'm not sure how to represent the object's velocity under quadratic drag, nor am I sure of the time constant. Is it still m/k, or is it different for quadratic drag?

This is my first post! I appreciate any and all help.
 
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The object will fall with terminal velocity when the gravitational force and the drag force become equal.
ie. mg=k*v^2
Now we know the terminal velocity
At any instant of time
F(net)=mg-kv^2
m.a(net)=mg-kv^2
m.v.(dv/ds)=mg -kv^2 (accn=v. dv/ds)
now integrate the above eqn using proper limits
 
Thank you very much!
 

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