Distance to 3rd and 5th nearest ion to S2- in ZnS structure

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SUMMARY

The discussion focuses on calculating the distances to the 3rd and 5th nearest sulfur ions (S2-) in a zinc sulfide (ZnS) structure, which has a cubic close-packed (ccp) arrangement. The distances are proposed to be √11a/4 and √19a/11, where 'a' represents the edge length of the unit cell. Participants emphasize the importance of geometric analysis and the Pythagorean theorem in deriving these distances, with some disagreement on the accuracy of the proposed values.

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Vishesh Jain
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Please post this type of questions in the HW section using the template and showing your work.
Hey folks

ZnS has a ccp structure with S2- ions forming FCC lattice with Zn2+ ions at half the tetrahedral voids

zbcell.gif


Attached is a table showing no. of nearest neighbours and their distance for an S2- ion

'a' is edge length of the unit cell

I want to know how the distance to the 3rd & 5th nearest ion is √11a/4 & √19a/11, i.e how to prove this.
upload_2018-10-13_16-17-34.png
Thanks ... any help is appreciated
 

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Have you you tried to follow the geometry? Often it is enough to find right right triangles and use Pythagorean theorem.
 
I think those numbers are wrong. They're not what I get (with quick mental arithmetic).
 
yes i did pythogarus & got it ... thanks ...
 

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