Dividing Polynomials: How to Solve (4s^3+4s^2+72)/(s+3)

[camel-man]

Mod note: Moved from a technical math section, so missing the template.

I have this question and the answer but my mathXL does not show me how it came to this conclusion.

(4s³+4s² + 72)/ s+3I got all the way to the answer 4s² - 8s

The correct answer is 4s² - 8s + 24

I just don't know the steps to getting the +24, because when worked the problem, you cannot minus 72 from 24s.

Anyone can help?

 

[fourier jr]

When you did your long division you might have left out the term with s in the numerator. When you work it out it should look like 4s³ + 4s² + 0s + 72.

 

[camel-man]

YEs that was the problem! thank you Fourier jr

 

[Mark44]

Mod note: Moved from a technical math section, so missing the template.

I have this question and the answer but my mathXL does not show me how it came to this conclusion.

(4s³+4s² + 72)/ s+3I got all the way to the answer 4s² - 8s

The correct answer is 4s² - 8s + 24

I just don't know the steps to getting the +24, because when worked the problem, you cannot minus 72 from 24s.

Anyone can help?

Check your division. Long division is difficult to type up on computers, so if you could take a picture of your work and post it, we could show you where you went wrong.

 

[Ray Vickson]

Mod note: Moved from a technical math section, so missing the template.

I have this question and the answer but my mathXL does not show me how it came to this conclusion.

(4s³+4s² + 72)/ s+3I got all the way to the answer 4s² - 8s

The correct answer is 4s² - 8s + 24

I just don't know the steps to getting the +24, because when worked the problem, you cannot minus 72 from 24s.

Anyone can help?

You wrote
\frac{4s^3+4s^2+72}{s} + 3,
which is very easy to complete. Did you really mean that, or did you intend
\frac{4s^3+4s^2+72}{s + 3}\;?
If so, use parentheses, like this: (4s^3+4s^2+72)/(s+3). This is a bit harder than the problem you wrote.