Do FM and AM Radio Stations Emit Different Numbers of Photons?

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Homework Help Overview

The discussion revolves around the comparison of photon emission between FM and AM radio stations with the same power output. The original poster questions whether the two stations emit different numbers of photons per second based on their respective frequencies, 105.2 MHz for FM and 701 kHz for AM.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between frequency, photon energy, and the number of photons emitted per second. The original poster attempts to apply the photoelectric effect formula (E=hf) to determine photon energy and raise questions about how to relate this to photon emission.

Discussion Status

Some participants have provided guidance on relating power output to photon emission, suggesting a mathematical approach involving the number of photons emitted per second. There is an ongoing exploration of how to formulate this relationship correctly, with participants questioning the implications of photon energy on the number of photons emitted.

Contextual Notes

Participants express uncertainty about their mathematical formulations and the appropriate representation of power in their equations. The discussion is framed within the context of homework constraints, focusing on understanding rather than providing direct solutions.

dirtywater101
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1. Two radio stations have the same power output from their antennas. one broadcasts on FM band at 105.2 MHz and other on the AM band at 701kHz. Which one emits more photons per second? Or do they emit the same amount of photons per second? Explain answer



2. I don't know if I've been doing it right. I've been using einstein's photoelectric effect to get the energy of each (E=hf), but I don't know how to relate this to the actual emition of photons. Please help! I'm the biggest novice :(



3. (105.2 x 10^6 s^-1) x (6.626 x 10^-34) = 6.97 x 10^-26

(701 x 10^3 s^-1) x (6.626 x 10^-34) = 4.64 x 10^-28
 
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You've found the energy of the FM station's photons, and the energy of the AM station's photons.

If you know that they both have the same power output, that means that each station is pumping out enough photons of energy E=hf every second, so that the energy per unit time, equals the output, P. How would you relate that mathematically? Try using an arbitrary symbol like n for the number of photons emitted per second.
 
hmmm... would it be

N photons/sec = Power / photon energy

i'm new to making equations so i don't really know how to write it out, but it is making some sense in my head and it's working. thanks a lot! I justdon't know how to put it into an acceptable equation form, aka what the value of P should be.
 
Just think about it. E=hf gives the energy EACH photon has. Which radio station gives off lower-energy photons? Since the photons have lower energy, does the station have to give off more or less photons to emit with the same power as the other station?
 

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