Does an object slow down when it enters water?

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When a dense object enters water, it initially slows down due to the forces of drag and buoyancy acting on it. Although the forces balance out when the object reaches a constant sinking speed, drag is dependent on speed and initially exceeds the object's weight. As the object slows, drag decreases until it equals the weight, allowing for constant sinking. The relationship between buoyancy and drag varies based on the object's density and speed. Understanding these dynamics is crucial for grasping concepts like terminal velocity.
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When a dense object sinks in water, it sinks at a constant rate, because the buoyancy and fluid drag counteract the weight of the object.

But if there is no resultant force, then why does the object slow down when it enters the water? Eg. if it's traveling at 2 m/s when it enters the water, shouldn't it continue to travel at 2m/s inside the water, because the forces are balanced?

Is there some kind of force that slows down the object WHILE it's entering the water, but doesn't do anything once the object is fully in the water?
 
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Nishantkumar19 said:
When a dense object sinks in water, it sinks at a constant rate, because the buoyancy and fluid drag counteract the weight of the object.
Why would you expect buoyancy and drag to be exactly equal to the weight of the dense object?
 
Okay so we did this experiment in school, and we dropped a steel ball into glycerin. After entering the water, it slowly sank at a constant speed, so that's how I know that the drag and buoyancy are equal to the weight.

Does drag increase with speed? Is it directly proportional or something?
That means the drag would initially be greater than the weight, but as the speed reduced, the drag would reduce until it's equal to the weight, and then the object would sink at constant speed. Also, is the buoyancy force stronger than the drag? Or is it the drag that mostly counteracts the weight?
 
Nishantkumar19 said:
Does drag increase with speed? Is it directly proportional or something?
It is not always as simple as a direct proportion. But yes, drag increases with speed.
That means the drag would initially be greater than the weight, but as the speed reduced, the drag would reduce until it's equal to the weight, and then the object would sink at constant speed.
Bingo. The reverse happens as well. If an object is gently released then drag is initially zero and increases until the object sinks at constant speed. Google "terminal velocity".
Also, is the buoyancy force stronger than the drag? Or is it the drag that mostly counteracts the weight?
It depends on the situation. For a piece of waterlogged wood that is just barely more dense than water, buoyancy will be dominant and drag will be relatively small. For a lump of lead that is much more dense than water, drag will be dominant and buoyancy will be relatively small. For a ping pong ball flung into the water at high speed, drag will dominate -- briefly.
 
Okay got it. Thanks
 
I do not have a good working knowledge of physics yet. I tried to piece this together but after researching this, I couldn’t figure out the correct laws of physics to combine to develop a formula to answer this question. Ex. 1 - A moving object impacts a static object at a constant velocity. Ex. 2 - A moving object impacts a static object at the same velocity but is accelerating at the moment of impact. Assuming the mass of the objects is the same and the velocity at the moment of impact...

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