Does Cl(X-A)=X-Int(A) work in infinite and uncountable dimensions?

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The statement Cl(X-A) = X-Int(A) holds true in both infinite and uncountable dimensions, as it is a fundamental property of topological spaces. The discussion clarifies that "dimension" in topology can be ambiguous, but most topological spaces do have a defined dimension. It is also noted that X should be a topological space while A is a subset of X for the statement to be applicable. The closure of the complement of A in X is indeed equal to the complement of the interior of A in any topological space. Overall, the property remains valid across various dimensional contexts.
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If I have the statement Cl(X-A)=X-Int(A)
X and A are topological spaces. Does this statement work in infinite dimensions and uncountable dimensions. I think it would just wondering.
 
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cragar said:
If I have the statement Cl(X-A)=X-Int(A)
X and A are topological spaces. Does this statement work in infinite dimensions and uncountable dimensions. I think it would just wondering.

What do you mean with "dimension" in topology in the first place?

But yes, the statement is always true as you can easily check for yourself.
 
Most topological spaces do define "dimension". Nor does it make sense to talk about X and A both being topologica spaces. I think you mean X is a topological space and A is a subset of X. But it is true that in any topological space that the closure of X- A is X- the interior of A.
 

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