Does ef|g Imply e and f Are Both Factors of g?

[blastoise]

I was wondering if this is a correct statement, I'm assuming it is for my proof.

Let e,f and g be non zero integers and assume ef|g is true.

I'm 100% positive this means $e$ and $f$ must both be a factor of $g$ .

May some one please confirm if I am correct or wrong please.

 

[tiny-tim]

hi blastoise!

Let e,f and g be non zero integers and assume ef|g is true.

I'm 100% positive this means $e$ and $f$ must both be a factor of $g$ .

you're 100% right!

(generally, if a|b and b|c, then a|c)