Does Hyperbolic Motion Cause Particle Radiation?

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SUMMARY

A particle in hyperbolic motion does radiate, as established by the equations provided by Griffiths. The relevant equations are w(t) = √(b² + (ct)²) for position and p = (μ₀q²a²γ⁶)/(6πc) for power radiated, where γ is the Lorentz factor. The power radiated remains constant, confirming that hyperbolic motion results in radiation. Historical perspectives, including Pauli's argument against radiation in hyperbolic motion, highlight ongoing debates in the field.

PREREQUISITES
  • Understanding of Lorentz transformations and the Lorentz factor (γ)
  • Familiarity with classical electromagnetism, specifically radiation equations
  • Knowledge of calculus, particularly differentiation
  • Basic concepts of special relativity and motion dynamics
NEXT STEPS
  • Study Griffiths' equations on particle radiation in detail
  • Explore the implications of the Lorentz factor in various motion scenarios
  • Research historical perspectives on radiation in hyperbolic motion, including Pauli's arguments
  • Learn about the mathematical treatment of radiation in relativistic contexts
USEFUL FOR

Physicists, students of electromagnetism, and anyone interested in the implications of special relativity on particle dynamics and radiation phenomena.

cragar
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Homework Statement


Does a particle in hyperbolic motion radiate?

The Attempt at a Solution


Griffiths say to use these 2 equations.
[itex]w(t)= \sqrt{b^2+(ct)^2}[/itex]
[itex]p= \frac{\mu_0q^2a^2 {\gamma}^6}{6\pi c}[/itex]
gamma is the Lorentz factor
w(t) is a function of time that describes position. now do I take the first derivative with respect to position to get v so I can plug that into the power equation and then take the derivative again to get a. I'm assuming that b is a constant. any help will be much appreciated.
 
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cragar said:
now do I take the first derivative with respect to position to get v so I can plug that into the power equation and then take the derivative again to get a. I am assuming that b is a constant.

Yes and yes. You should find that the power radiated is constant(!)
 
cragar said:

Does a particle in hyperbolic motion radiate?

Cragar, that's a fairly famous question that I don't think has been definitively answered. I'm certainly not qualified to answer it. I think Pauli once argued that there should be no radiation for hyperbolic motion. For an interesting discussion, see http://www.mathpages.com/home/kmath528/kmath528.htm
 

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