MHB Does this series converge almost everywhere?

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The series ∑_(n=1)^∞ cos^n(2^n x) converges almost everywhere but diverges on a dense set of x values. For x in the form of aπ/2^b, where a and b are integers, the terms of the series equal 1 infinitely often, demonstrating divergence on a dense set. The discussion emphasizes the challenge of proving almost everywhere convergence. Participants suggest using LaTeX for clearer mathematical expression. Overall, the thread focuses on the convergence properties of the series in relation to specific values of x.
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Show that ∑_(n=1)^∞ cos^n (2^n x) converges for a.e. x, but diverges on a dense set of x’s .

Show that [math]\sum_{n=1}^\infty \cos^n (2^n x)[/math] converges for a.e. x, but diverges on a dense set of x’s .
 
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Re: Show that ∑_(n=1)^∞ cos^n (2^n x) converges for a.e. x, but diverges on a dense set of x’s .

Hi Jack,

Did you know that you can use Latex on MHB? The way you write is pretty close already to the correct Latex syntax so if you just learn a few common pieces of code you'll be able to use it immediately.

I rewrote the sum in your OP as:

\sum_{n=1}^\infty \cos^n (2^n x)

Jameson
 
Re: Show that ∑_(n=1)^∞ cos^n (2^n x) converges for a.e. x, but diverges on a dense set of x’s .

Jack said:
Show that [math]\sum_{n=1}^\infty \cos^n (2^n x)[/math] converges for a.e. x, but diverges on a dense set of x’s .
If $x$ is of the form $\dfrac{a\pi}{2^b}$ (where $a$ and $b$ are integers) then $\cos^n (2^n x)$ will take the value 1 infinitely often. That deals with showing that the series diverges on a dense set.

Convergence a.e. looks harder. I will pass on that for now.
 

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