- #1

Rijad Hadzic

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- 20

## Homework Statement

Say you have a fn

FoG = x+2/x+1 + x+1/x+2

if x = -1, the first one is undefined. But the second one would end up as 0, a real number

I'm trying to understand, would x = -1 make the whole term FoG undefined? because only x+2/x+1 would be undefined, x+1/x+2 would be = to 0, so why isn't the answer zero, instead of undefined?Also one more question so I don't have to make threads.

I'm freshening up on my calculus.

" Express the function in the for FoGoH: ( sec(x^(1/2)) ) ^4 "

the book did this:

h(x) = x^(1/2) g (x) = sec(x) f(x) = x^4

but I did: h(x) = x g(x) = x^1/2 f(x) = (sec(x) ) ^4

you get the same answer... surely I'm not wrong am I?

## Homework Equations

## The Attempt at a Solution

Plugged FoG into my calculator with x= -1. Got "undefined function"

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