MHB Domain of Square Root Function

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The domain of the function f(x) = (3x + 5)^(1/2) requires that the radicand, 3x + 5, is non-negative. To find the domain, solve the inequality 3x + 5 ≥ 0. This simplifies to x ≥ -5/3. Therefore, the domain of the function is all real numbers x such that x is greater than or equal to -5/3. The function is defined for x in the interval [-5/3, ∞).
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Find the domain of the function f(x)= (3x+5)1/2.

Not quite sure how to even start this...
 
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Hint: To get a real value for the function, the radicand (expression under the radical) cannot be negative. So solve:

$\displaystyle 0\le3x+5$
 

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