Dosage and total Energy from radioactive medicine.

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SUMMARY

The discussion focuses on calculating the dosage and total energy from a radioactive pharmaceutical containing P32, which emits beta rays with an energy of 705 keV. The half-life of P32 is 14.28 days, and the initial activity is 1.34 mCi. The user seeks assistance in determining the number of emitted electrons over 7 days, the total energy absorbed by the patient's body, and the absorbed dosage in rem for 110 grams of tissue. Key calculations involve the decay constant and the number of nuclei present at time zero.

PREREQUISITES
  • Understanding of radioactive decay and half-life concepts
  • Familiarity with beta radiation and its energy calculations
  • Knowledge of dosage calculations in rem
  • Proficiency in using exponential decay equations
NEXT STEPS
  • Calculate the number of emitted beta particles using the decay formula N=N0e^(-(lambda)(t))
  • Determine the total energy absorbed using the formula Energy = (number of particles) x (energy per particle)
  • Convert the absorbed energy into dosage in rem using the appropriate conversion factors
  • Research the implications of radioactive pharmaceuticals in medical treatments
USEFUL FOR

Medical physicists, radiologists, and healthcare professionals involved in treatment planning with radioactive materials, as well as students studying radiation physics and dosimetry.

NickMcCartney
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I can't seem to get this started in the right direction. Any help is appreciated.

As part of a treatment program, a patient ingests a radioactive pharmaceutical containing P32,15, which emits beta rays with an of 1.50. The half-life of is 14.28 , and the initial activity of the medication is 1.34 .

Part A
How many electrons are emitted over the period of 7.00 days?

Part B
If the rays have an energy of 705 keV , what is the total amount of energy absorbed by the patient's body in 7.00 ?

Part C
Find the absorbed dosage in rem, assuming the radiation is absorbed by 110 grams of tissue.
 
Last edited:
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Here is what I have done so far.

Part A.

Converted half life (T 1/2) into seconds. = 1.234e6 s
Found the decay constant (lambda) = ln(2)/1.234e6 = 5.617e-7
Found N0 (nuclei present at t=0) = R0/lamda = 2.386e12
Found N= A-Z = 32-15=17

Tried to plug into equation: N=N0e^(-(lambda)(t)) where I put the 7 days (in seconds) into t which came out to 1.7e12, which was wrong. I don't know where to go from here.
 
Last edited:

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