High School Doubt regarding Rutherford's Alpha Scattering Experiment and Impact Parameter

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The discussion clarifies that a large impact parameter in Rutherford's Alpha Scattering Experiment results in small-angle scattering due to the inverse square relationship of the Coulomb force with distance. As the impact parameter increases, the distance between the alpha particle and the nucleus also increases, leading to a significant reduction in the Coulomb force. Consequently, the alpha particle experiences weaker interactions, resulting in minimal deflection. Conversely, a small impact parameter leads to stronger forces and larger scattering angles. This understanding is crucial for interpreting the behavior of alpha particles in nuclear interactions.
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It is mentioned in my Textbook that if alpha-particle has large impact parameter, it gets scattered through small angles and vice versa.

I understand that impact parameter is defined as the perpendicular distance between the path of a projectile and the center of the nucleus.

I am unsure how the aforementioned fact is explained?
 
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How does the Coulomb (electric) force between the alpha-particle and nucleus vary with distance?
 
jtbell said:
How does the Coulomb (electric) force between the alpha-particle and nucleus vary with distance?
It is inversely proportional to the square of the distance between them.
 
So if the impact parameter becomes larger, what happens to the force?
 
jtbell said:
So if the impact parameter becomes larger, what happens to the force?
Force reduces drastically. Hence the scattering occurs through small angle. Understood.
 
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