DPPH (a chemical salt [(C6H5)2N-NC6H2 (NO2)3]) and EPR/ESR

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SUMMARY

The discussion focuses on the use of DPPH (a chemical salt [(C6H5)2N-NC6H2(NO2)3]) in Electron Paramagnetic Resonance (EPR) or Electron Spin Resonance (ESR) experiments. The primary concern is whether using a frequency of 1800 MHz will yield the same results as the typical frequency range of 35 to 75 MHz. It is established that the energy required to change the spin state of an electron must match the resonance frequency for absorption to occur. Calculating the RF energy and comparing it to the ionization energy of DPPH is essential for understanding potential ionization at higher frequencies.

PREREQUISITES
  • Understanding of Electron Paramagnetic Resonance (EPR) principles
  • Knowledge of DPPH chemical structure and properties
  • Familiarity with RF energy calculations and resonance concepts
  • Basic principles of ionization energy in chemistry
NEXT STEPS
  • Calculate RF energy using the relationship between energy and frequency
  • Research the ionization energy of DPPH and related hydrazides
  • Explore the effects of static magnetic field strength on resonance absorption
  • Study the impact of light and heat degradation on chemical compounds in experiments
USEFUL FOR

Chemists, physicists, and researchers involved in EPR/ESR experiments, particularly those studying radical species and their behavior under varying magnetic fields.

hagopbul
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I am doing this test on DPPH (a chemical salt [(C6H5)2N-NC6H2 (NO2)3])
The goal of the experiment is to study The Electron Paramagnetic Resonance or
The Electron Spin Resonance



Buy using this way:
see it in the file
 

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I don't think the higher frequency will matter. I don't know physics like others who might comment, but I'd be more worried about changing values in experiments from degradation due to light or heat. I can help more with presentation. Say "By" instead of "Buy," and you might change "we effect" to "we apply," and then clarify that you apply a polarizing (I think) field, and then you apply a linear pulse. Not sure if those terms are better, but there should be something better for the subsequent idea about the 90 degree orientation. Maybe something about how the magnetization works in a cavity?

Anyway, no one else is writing so I thought I'd throw-in my thoughts. We're generally interested in how DPPH behaves because we use it in our MRFM experiments.
 
hagopbul said:
I am doing this test on DPPH (a chemical salt [(C6H5)2N-NC6H2 (NO2)3])
The goal of the experiment is to study The Electron Paramagnetic Resonance or
The Electron Spin Resonance



Buy using this way:
see it in the file

Your question was,

The question that I have in my mind that if I use 1800 MHz (The magnetic field F) will I have the same result and can the DPPH or one of its atoms become ionized when I use a 1800 MHz.
What I understand about ESR is that the energy used to change the spin state of the electron in question must be in resonance to be absorbed. If the electron will absorb the RF (magnetic component) energy at 1800 MHz then you will have a result. If the usual energy of this absorption is significantly different than 1800 MHz, and it appears to be so, then nothing will happen. Your frequency range is from 35 to 75 MHz in the table you provided. 1800 MHz appears to be significantly different from this and so even higher level harmonics of the 35 to 75 MHz frequencies will not likely be absorbed in your experiment unless you significantly lower the strength of the static magnetic field.

You can answer your question about ionizing the compound for yourself if you calculate the energy in the RF energy (you should already know of a relationship between energy and frequency) and compare that to a typical ionization energy of this hydrazide. Watch your units (I would use Electron Volts).
 

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