Main Question or Discussion Point
Well I'm supposed to draw Thomson cross section in polar plot by matlab software. Have I done it right? I mean does this figure that I got seem to be in polar plot or not?
t = 0:.01:2*pi; r = 2.8179e-13 x = t,0.5*power(r,2)*(1+power(cos(t),2)) polar(t,x)
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