Draw Thomson cross section in polar plot by matlab

[Lisa!]

Well I'm supposed to draw Thomson cross section in polar plot by MATLAB software. Have I done it right? I mean does this figure that I got seem to be in polar plot or not?

t = 0:.01:2*pi;
r =  2.8179e-13
x =  t,0.5*power(r,2)*(1+power(cos(t),2))
polar(t,x)

Thanks

 

[Lisa!]

Have I posted it in the right place?

 

[oswaler]

for your question. It appears that you have correctly plotted the Thomson cross section in polar coordinates using MATLAB. The resulting figure does indeed represent a polar plot, as the data is plotted on a circular grid with the angle as the independent variable and the distance from the origin as the dependent variable. Well done! It is important to always double check your results and make sure they align with the expected outcome. Keep up the good work in using MATLAB for scientific visualization.