Dropping coal on a platfrom (energy cons)

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SUMMARY

The discussion focuses on the energy conversion process when a railroad hopper car releases coal onto a platform. The hopper car, weighing 20,000 kg and carrying 10,000 kg of coal, travels at 9 m/s. Upon releasing the coal over 5 seconds, the total energy converted to heat is calculated to be 895,000 Joules, accounting for both kinetic and potential energy losses as the coal comes to rest. The average horizontal force exerted on the platform during this process is determined to be 9,000 N.

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Homework Statement


A railroad hopper car weighs 20000 kg when empty and contains 10000 kg of coal. As it coasts along the track at 9 m/s the hopper opens and steadily releases all the coal onto a platform below the rails over a period of 5 s.


Homework Equations


d) If the coal fell 5 m, what was the total energy converted to heat in the process of the coal coming to rest?


The Attempt at a Solution



Ive already got the first 3 parts of this question. they are
How fast does the car travel after all the coal is dumped?
=9m/s

What was the momentum absorbed by the platform?
=9000kg/m/s

If the coal comes to rest 1 second after the dumping is finished, what was the average horizontal force on the platform?
=9000N

My question b4 attemptin solution is --how can energy be conserved if coal is at rest? (no potential, and no kinetic).
If it cant, then that would mean all the energy must have gone somewhere.. --heat.

So 9000N*5m = 45000J.
This is wrong.
??
 
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You are correct about energy being conserved, what two types of energy does the coal have when it is moving in the train?
When it comes to rest below the train it loses both of these - to heat as you said.
 
AHA potential AND kinetic because car moving 9ms
so Ek + Ep = 895000J

thanks!
 

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