Duct pressure unit conversions not checking out

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Homework Statement
A vacuum gage at the intake duct to a fan gives a reading of 6 in of water. The surrounding atmospheric pressure is ##14.5 lbf/in^2## Determine the absolute pressure inside the duct, in ##lbf/in^2.## The density of water is ##62.39lb/ft^3##, and acceleration of gravity is ##32.0 ft/s^2##.
Relevant Equations
$$p=p_{atm}+ \rho gL$$
These units complicate everything and I simply cannot get them to check out for the life of me. After making some conversions I got to this point:
488C6200-A37A-464D-8CF8-3D2B30690482.jpeg
 
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Ask yourself what a vacuum gauge measures.
Wrt units, how do you convert lbm to lbf? (You could have saved yourself some arithmetic.)
How do you convert ft2 to in2?
 
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haruspex said:
Ask yourself what a vacuum gauge measures.
Wrt units, how do you convert lbm to lbf? (You could have saved yourself some arithmetic.)
How do you convert ft2 to in2?
I ended up solving the problem by realizing 1 lbm= 1 lbf on Earth essentially and the density can be expressed in terms of ##lbf/ft^3##.
Thanks a lot.
 
cwill53 said:
I ended up solving the problem by realizing 1 lbm= 1 lbf on Earth essentially and the density can be expressed in terms of ##lbf/ft^3##.
Thanks a lot.
What answer did you get? You did not respond to my remark about what a vacuum gauge measures.
 
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The correct starting equation, in proper English units should be $$p=p_{atm}-\frac{\rho gL}{g_c}$$where $$g_c=32\ \frac{lb_m\ ft}{lb_f\ sec^2}$$So, $$p=p_{atm}-\frac{(62.4)(32)(0.5)}{32}\frac{1\ ft^2}{144\ in^2}=14.5-0.2=14.3\ psi$$
 
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haruspex said:
What answer did you get? You did not respond to my remark about what a vacuum gauge measures.
I got the answer of ##14.2834lbf/in^2##

A vacuum gauge measures pressures that are lower than atmospheric pressure.