Hello Everyone!
this question is using Indonesian language, i have translated the question at "Homework Statement". The container is filled by water (in Indonesian, "Air" means "Water")
i know the the pressure at point X, Y and Z depends on their corresponding depth. my best answer is :
Pz >...
First, I calculated the number of moles of glucose.
n = m / M
n = 1.8 / 180
n = 0.01 moles of glucose
So I checked the combustion reaction.
1 C6H12O6 + 6 O2 -> 6 CO2 + 6 H20
1 + 6 -> 6 + 6
0.01 + 0.06 -> 0.06 + 0.06
I considered the number of moles at the end of the reaction.
I subtracted...
In the movie The Abyss an oil rig crew works and lives at the bottom of the ocean in a deep sea structure. There is a compartment where there is an opening in the floor allowing the crew to lower a submersible craft without going through any kind of air locks etc.
We all should know from high...
Some notation:
- the difference between the heights of mercury, which is effectively the height of the mercury in the open end of the tube is ##h_{diff}##
- the volume of gas inside the sealed off end is ##V_{inside}##
- the volume of gas when let outside, "normal volume", is ##V_{outside}##
-...
$$\rho_{Hg} gh_{actual} = \rho_{Hg} gh_{measured} + \rho_{air} gh_{air}$$
Note: by "actual", I mean "theoretical", i.e. what the barometer would measure were there no air inside it. By "measured" I mean "as measured by the faulty barometer, i.e. with some air introduced".
I believe this...
Let's start with a horizontal tube with a constant diameter. I'm not sure if it's important, but let's assume it's frictionless. I will have some fluid flowing in this tube and if it's important, we can make the fluid incompressible, inviscid, irrotational, etc.
To create a flow in the tube...
Here is the setup:
Apply Bernoulli Principle to the top (free surface) of the two pitot tubes (1 for static and 2 for dynamic with the points colored in red): $$\frac{p_1}{\rho_w g}=h+\frac{p_2}{\rho_w g}$$
The difference in air pressure would give the following:$$p_1=p_2+h\rho_{air} g$$...
I hope you guys don't mind a bizarre question from a novice. I've learned just enough about fluid dynamics to be dangerous.
Assume that we have a straight, rigid tube with a constant inner diameter. It's not long, let's say it's around a foot (in case that matters). We cut a chunk out of the...
Assume the jet is straight but the radius of the jet varies over it's length (like a jet of water falling which narrows due to gravitational acceleration). Also ignore viscosity. A pressure gradient would be required to accelerate the fluid radially. Because during an expansion transformation...
According to one explanation, the left hand acceleration terms of Navier Stokes equations are the called the inertial terms. If you were to balance forces on the fluid particle, they would have to be equal and opposite to the forces on the right hand side (pressure gradient, viscous, and body)...
Summary:: i) Set up a differential equation that describes how the pressure ##p## varies with the distance
r from the center of the planet. Hint: You can base your reasoning on static
equilibrium and Archimedes' principle.
ii)Calculate how the atmospheric pressure p and the density of the...
Hello.
How does a bullet propell inside a bore? What determine its velocity? I read that a bullet in cal .44 propelled by black powder from a 3” barrel is as powerful as a .25 ACP, however with a longer barrel, the velocity increase significant. With a 8” barrel a .44 black powder bullet is as...
hi guys, i cant understand why they calculate F yin this way, the part of floor that is the vertical proyection has less water than the floor in the left so i tought Fy would be less, please can someone explain this concept to me?
So I already have a solution available to this problem and the link for the solution is:
I have understood everything in the video except the part where they are equating the force
dF=GM/r²*dm
According to my reasoning the inner part of the sphere (the part below the dm element we have taken)...
If Evangelista Torricelli truly created a vacuum, then there would be nothing in it, yet you can see through it which means light is obviously still in there (and who knows what else), right?
If there was truly nothing in it, and glass is a highly viscous fluid, and fluids conform to fill empty...
Answer : Using Pascal's law, this is my answer : ##\color{blue}{\boxed{\vec F_a = \vec F_c < \vec F_b}}##.
Reasoning :
Forces ##F_a## and ##F_c## are equal because the pressures required at the two cylinders for case (c) is the same as that required in (a). It doesn't matter how many of those...
I've first calculated the partial pressures of each gas:
##N_2: 0.4\times 7.4\times 10^4=3.0\times 10^4 Nm^{-2}\\##
##O_2: 0.35\times 7.4\times 10^4=2.6\times 10^4 Nm^{-2}\\##
##CO_2: 0.25\times 7.4\times 10^4=1.9\times 10^4 Nm^{-2}\\##
From here, I do not know how to continue. Could someone...
First, I tried using the Archimedes principle and calculated the weight of the surrounding air displaced when taking off.
##W = 2500\times 1.29\times 9.81 = 31637.25 N##
But then, I got stuck and do not know how to proceed from here on.
I don't want the full solution yet but can I get some...
I’m currently studying Fluid Mechanics, during an analysis I came across this
We now consider an example that combines centrifugal force and gravity: a liquid in a drum (centrifuge) rotates with constant angular velocity ##\omega## about a vertical axis. The centrifugal force per unit of...
These are the images from Sommerfeld’s Lectures on Theoretical Physics, Vol 2 chapter 2, section 6, Equilibrium of Incompressible Fluids.
Image 1
Image 2
Doubt 1 : What does it mean for a force to act on a fluid volume? Force acts on a point, force may act on a surface but I’m unable to...
First off im not sure if the equation is even suitable for solving this problem. Secondly, I have no idea how to determine the tension the shrink film can provide. Furthermore, I also think the radius of the film tube has a influence on the pressure, I guess in this problem the tube is regarded...
(a) Situation (2) is my answer (which cannot be in static equilibrium). The pressures in the lower dashed line (##P_2##) has to be the same on either side (for equilibrium). That means the pressure due to the red liquid is equal to the pressure due to the same length of air column (length)...
Since the assignment asks the work done by the gas, that should be equal to P1*(V2-V1) aka the area under the P1 line. Do I have to subtract the work done to the system or is this the solution already? If so, why do I need P2?
Hello!
I have a volume of 50 liters which I pressurize with air so that I read 1 bar on the manometer.
But there is a leakage in the volume so after 30 sec the manometer shows 0,5 bar.
What is then the air flow ( liter / min) of the leakage?
∇p=j×B (eq. 1)
K=nI
BSolenoid=μnI⇒μK (eq. 2)
∇p=-2p0r/(a2) (eq. 3)
Combining these three equations:
j=-2p0r/(a2μK) (θ hat direction)
Feel like this is too simple and might be missing a step any help would be much appreciated!
$$ H = \frac { V^2 - V_0^2 sin \Theta} {-2g} $$
$$ H = \frac {V_0^2 sin \Theta} {2g} $$
So, I need to calculate ## V_0 ##
I'm thinking about pressure.
$$ P = \rho g \Delta h $$
$$ \Delta h = h - L sin \Theta $$
$$ F_A = P S_A $$
$$ F_A = P S_B $$
Dead End here...
Summary: Im not a physics student but I really need to prove that aluminium will not deform 10m underwater
Hi Im doing a project of a product which will sink underwater.
It will be a sealed cylindrical vessel, length 2m, width 1m, thickness 0.02m.
Aluminium 6061t will be used with a yield...
If we take a slab of air with cross-sectional area of A and height dz in our atmosphere. Now, what we do is make an argument like this :-
Pressure from below must balance both the weight and Pressure from above to keep the slab at rest. ( I have added an attachment for clarification)
And...
I want to ask why is it that we use gauge pressure instead of absolute pressure in CV analysis for momentum conservation of fluids.
I did read that because P(atm) would be present everywhere so it won't have a net effect on the CV but it's highly non intuitive as I can't apply force balance on...
What's really the difference between pressure and normal stress? Also I know pressure acts normal to a surface from the outside
Do normal stress acts from inside?
I'm reading bird transport phenomena and this is confusing