∇p=j×B (eq. 1)
K=nI
BSolenoid=μnI⇒μK (eq. 2)
∇p=-2p0r/(a2) (eq. 3)
Combining these three equations:
j=-2p0r/(a2μK) (θ hat direction)
Feel like this is too simple and might be missing a step any help would be much appreciated!
$$ H = \frac { V^2 - V_0^2 sin \Theta} {-2g} $$
$$ H = \frac {V_0^2 sin \Theta} {2g} $$
So, I need to calculate ## V_0 ##
I'm thinking about pressure.
$$ P = \rho g \Delta h $$
$$ \Delta h = h - L sin \Theta $$
$$ F_A = P S_A $$
$$ F_A = P S_B $$
Dead End here...
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