Dynamics - Normal and Tangential Motion

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SUMMARY

The discussion focuses on calculating the maximum acceleration of a car negotiating a curve without sliding, given a maximum frictional force of 1753 lb, a speed of 75 ft/s, and a road curvature of ρ=560 ft. The normal acceleration (an) is calculated as 10.04 ft/s², while the tangential acceleration (at) is determined to be 14.85 ft/s². The total maximum acceleration (a) is confirmed to be 17.90 ft/s², combining both normal and tangential components. Participants verify the calculations, emphasizing the importance of accurate values in determining the tangential acceleration.

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  • Understanding of Newton's second law (ƩFn = man)
  • Knowledge of circular motion and centripetal acceleration
  • Familiarity with frictional forces in automotive dynamics
  • Basic algebra for solving equations involving acceleration
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  • Learn about friction coefficients and their impact on vehicle dynamics
  • Explore advanced topics in dynamics, such as angular momentum
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Students in physics or engineering, automotive engineers, and anyone interested in understanding vehicle dynamics and acceleration calculations.

aaronfue
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Homework Statement



The tires on a car are capable of exerting a maximum frictional force of 1753 lb. If the car is traveling at 75 ft.s and the curvature of the road is ρ=560 ft, what is the maximum acceleration that the car can have without sliding?

Homework Equations



ƩFn = man

The Attempt at a Solution



Ff = 1753 lb
v = 75 ft/s
ρ=560 ft
wcar = 3150 lb

an = \frac{v^2}{ρ} = \frac{75^2}{560} = 10.04 ft/s2

I believe that the acceleration would be the magnitude of the tangential and normal acceleration.

ƩFn = man = \frac{3150}{32.2}*10.04 = 982.2 lb

1753 = √Ft2 + 982.22

Solving for Ft = 1452 lb;

Now solving for at → 1452 = \frac{3150}{32.2}*at
at = 14.85 ft/s2

a = √at2 + an2 = √14.852 + 10.042 = 17.90 ft/s2

I'd appreciate it if someone could verify my work.
 
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I get the same answer as you. I think the question is asking for the maximum tangential acceleration which is 10.04 ft/sec^2.
 
LawrenceC said:
I get the same answer as you. I think the question is asking for the maximum tangential acceleration which is 10.04 ft/sec^2.

Tangential was actually 14.85 ft/s^2.

And it makes sense too.

Thanks.
 
Last edited:
aaronfue said:
Tangential was actually 14.85 ft/s^2.

And it makes sense too.

Thanks.

I typed the wrong number...should have typed 14.85 ft/s^2.
 

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