Dynamics - Using the coefficient of friction

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SUMMARY

The discussion focuses on a physics problem involving a 260 kg safe being lowered down a 20.0 m skid from a height of 2.0 m, with a coefficient of friction of 0.25. It concludes that to maintain a constant speed, a force must be applied parallel to the skids to counteract the frictional force. The frictional force is calculated using the equation F = μN, where N is the normal force. The required force to pull the safe down the skids is determined to be equal to the frictional force, ensuring the safe moves at a constant speed.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with the concept of friction and the coefficient of friction
  • Knowledge of basic physics equations, particularly F = μN
  • Ability to calculate normal force in inclined scenarios
NEXT STEPS
  • Study the effects of different coefficients of friction on motion
  • Learn how to calculate normal force in various scenarios
  • Explore the implications of constant speed on force application
  • Investigate real-world applications of friction in engineering
USEFUL FOR

Students studying physics, educators teaching mechanics, and anyone interested in understanding the practical applications of friction in motion scenarios.

K.QMUL
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Homework Statement



You are to lower a safe of mass 260kg at constant speed downs skids 20.0m long, from a truck 2.0m high.
a) If the coefficient of friction between the safe and the skids is 0.25, do you need to pull the safe down or hold it back?

b)How great a force parallel to the skids is needed?

Homework Equations



F=μN

The Attempt at a Solution



Please see image
 

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Looks correct.
 
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