- #1
adz7861
- 5
- 0
- Homework Statement
- Expression for the total loss of energy after the collision
- Relevant Equations
- p=mv
KE=1/2mv^2
Last edited:
EENGA 2019 Momentum question -- collision of two masses
- Thread starter adz7861
- Start date
-
- Tags
- Collision Momentum Two masses
Click For Summary
SUMMARY
The discussion centers on solving a momentum problem from EENGA 2019, specifically calculating the total loss of energy after a collision between two masses. Participants analyze the correct application of the kinetic energy formula, KE = 1/2mv^2, and the momentum equation, p = mv. The confusion arises from the distinction between the masses used in the calculations, particularly between the moving particle's mass (mE) and the stationary particle's mass (ME). Ultimately, the correct answer is identified as option B, which requires careful manipulation of the equations to match the provided choices.
PREREQUISITES- Understanding of momentum conservation principles
- Familiarity with kinetic energy calculations
- Ability to manipulate algebraic fractions
- Knowledge of collision types (elastic vs. inelastic)
- Review the principles of momentum conservation in collisions
- Learn how to derive kinetic energy before and after collisions
- Practice manipulating algebraic fractions for physics problems
- Explore examples of elastic and inelastic collisions
Students studying physics, particularly those focusing on mechanics and collision problems, as well as educators looking for examples of energy loss calculations in collisions.
- #2
- 42,802
- 10,495
Ok, but which option does that match?adz7861 said:
- #3
adz7861
- 5
- 0
haruspex said:
I keep getting my answer to be C, when the real answer is B
- #4
- 42,802
- 10,495
Then you are making a mistake beyond the working you posted. What you posted matches B.adz7861 said:
- #5
adz7861
- 5
- 0
The only difference in B & C are the different masses on the nominator. What I've got is the mass of the moving particle (mE) as the nominator. The answer states that it should be ME which is the mass of the stationary particle.haruspex said:
So my working out must be incorrect, unless I'm missing a further step.
I've basically done the KE after the collision - KE before collision to give me a value for the energy loss. I am confused on what to do further after my last equation.
- #6
ehild
Science Advisor
Homework Helper
- 15,536
- 1,917
Can you subtract fractions?adz7861 said:
Write the second term as a fraction with denominato m+M. Show your working.
- #7
- 42,802
- 10,495
Exactly. Get your answer into the form of the choices, a single fraction.adz7861 said: