Eigenvectors and the dot product

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
1 reply · 4K views
hover
Messages
342
Reaction score
0

Homework Statement



Suppose the the matrix A is symmetric, meaning that
A =

a b
b d

Show that for any symmetric matrix A there are always real eigenvalues. Also, show that
the eigenvectors corresponding to two di erent eigenvalues are always orthogonal; that is,
if V1 and V2 are the eigenvectors for eigenvalues [tex]\lambda[/tex]1 and [tex]\lambda[/tex]2, with [tex]\lambda[/tex]1 not equal to [tex]\lambda[/tex]2, then the dot
product V1 * V2 = 0.
HINT: Compare [tex]\lambda[/tex]1V1*V2 to V1*[tex]\lambda[/tex]2V2 .


Homework Equations



-

The Attempt at a Solution



I was able to show that any eigenvalue from this matrix would always be positive. That wasn't too bad. Its the second part that is tripping me up. I don't get how the hint is really all that helpful. I want to find values of V1 and V2 don't I? I'm confused.
 
Physics news on Phys.org
You don't need to find the eigenvectors explicitly. All you need to show is that their dot product is zero.

Consider <Av1,v2> and <v1,Av2> and, using the fact that A is symmetric, show that they are equal.