Elastic Collisions: What Went Wrong in My Calculation?

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Homework Help Overview

The discussion revolves around an elastic collision problem involving two objects with given masses and initial velocities. The original poster attempts to find the final velocities of both objects after the collision using conservation of momentum and kinetic energy equations.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster describes their attempts to solve the problem using two conservation equations, expressing confusion over obtaining two different sets of final velocities that both seem valid when checked against the original equations. They question why there are two answers and whether one of the objects should be moving in a negative direction after the collision.

Discussion Status

Some participants have confirmed the original poster's setup is correct but noted discrepancies in the solutions when they attempted to verify them. Others have suggested an alternative approach to simplify the problem by combining the equations to avoid quadratic complications.

Contextual Notes

The original poster expresses uncertainty about potential computational errors and the implications of their findings, indicating a desire for clarification without definitive conclusions being drawn.

fuzzish
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Just to begin, uhh. I'm 75% sure my work makes logical sense [I hope], and that my problem lies in a computational error. But I really don't know why my answers aren't working out. I've now gone through the problem in 3 different ways, and I keep getting the same answer, but it's apparently still incorrect. If it is an arithmetic error, sorry for making you read through all of this to fix such a stupid mistake >.>

Homework Statement



A 12.7g object moving to the right at 26.5cm/s overtakes and collides elastically with a 10.5g object moving in the same direction at 10.7cm/s.

Find the velocity of the faster object after the collision. Answer in units of cm/s.

Find the velocity of the slower object after the collision. Answer in units of cm/s.

Homework Equations



m1v1 + m2v2 = m1v3 + m2v4

.5m1v1^2 + .5m2v2^2 = .5m1v3^2 + .5m2v4^2

And, sorry in advanced for the ugly way that equation appears. And for the work that is likely to look just as messy.

The Attempt at a Solution



m1 = 12.7g ; v1 = 26.5cm/s
m2 = 10.5g ; v2 = 10.7cm/s

I plugged those two into the first equation and got:
448.9 = 12.7v3 + 10.5v4

Rearranged for v3:
v3 = 35.35 - 0.827v4

I then plugged in the m1, v1, m2, and v2 into the second equation and got:
5060.36 = 6.35v3^2 + 5.25v4^2

Plugged in the v3 from the previous equation:
5060.36 = 6.35 ( 35.35 - 0.827x )^2 + 5.25 x^2

AND HEREEEE I FIND MY PROBLEMO.
My TI-89 keeps giving me two answers:
v3 = 28 [in which case v4 = 8.89]
or
v3 = 10.7 [and thus v4 = 29.8]

Problemo Uno: Why are there two answers? O_o? And both seem to work when plugged back into the original equations? This point makes me most uncomfy and confused.

Problemo Dos: If it's an elastic collision, shouldn't one of the objects be moving in a negative direction now? Perhaps my thought process is wrong here though, but idk.

/////////////////////
Thanks in advanced to whoever offers help yay. And I know I'm a noob leeching off these forums, so just so I don't feel like I'm nomming up the answer and running away, I'll stay around to help someone else if I can xD.
 
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Your set-up is correct, but neither of your solutions work when I plug them in here.
 
Auurrghhghghghhhh. Fifth round of calculator plug and chug, and I still got 2 answers, but the one that worked worse out of the two turned out to be the right pair. This. Is. Really. Weird. Maybe I need a new calculator, idk.

Anyways, thanks for rechecking my set-up :].
 
By the way, for one-dimensional elastic collisions, you can combine the two equations to come up with a third one that relates the objects' relative velocities. It's linear so you can avoid the quadratic messiness. Check your notes or your book for its derivation.
 

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