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It is my understanding (?) that, when an electron is annihilated, the resulting photons do not react with gravity. Why isn't that quality conserved?
The discussion centers on the effects of electron-positron annihilation on gravity and the behavior of resulting photons. Participants clarify that photons, despite having zero mass, are influenced by gravity due to their energy. The annihilation produces two photons that move in opposite directions to conserve momentum, while a gravitational wave expands outward from the annihilation event. The conversation raises questions about the nature of the gravitational wave and its relationship to the binding energy of the particle pair.
PREREQUISITESPhysicists, students of particle physics, and anyone interested in the interplay between quantum mechanics and gravitational theory.
Vanadium 50 said:Your understanding is incorrect. Where did you read that?
Antiphon said:The title of the thread stands as an interesting question.
A particle-antiparticle pair is hald apart by a magic thread. The system has an almost exactly spherical gravitational field.
At the moment of anhiliation, a pair of photons fly away is opposite directions to preserve momentum, spin, charge and everything else.
A gravity wave should expand spherically outward from the moment of anhilation to terminate the gravitation from the defunct particles.
Does this wave contain the binding energy of the particle pair or is it a fraction of their rest masses? Or does it coincide with and somehow represent the outgoing electromagnetic front which is also spherical (even though the two photons will eventually be detected in some colinear trajectory.)
I think I know the answer but I'd like an expert opinion.