Elliptical orbit parameterized by time

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Discussion Overview

The discussion revolves around how to express the parametric equations for an elliptical orbit in terms of time, contrasting it with the simpler case of circular orbits. Participants explore the challenges of deriving an analytic formula for position as a function of time for elliptical orbits.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • Some participants note that expressing an elliptical orbit parametrically in terms of time is more complex than for circular orbits, which can be represented simply as $$(x,y) = (cos(\omega t),sin(\omega t))$$.
  • One participant mentions that their attempts yield non-analytic results, suggesting that the analysis based on Newton's laws does not provide a straightforward time-dependent position formula.
  • Another participant references "The Kepler Equation" as a relevant topic, implying that it may offer insights or solutions to the problem at hand.

Areas of Agreement / Disagreement

Participants generally agree that deriving a time-dependent parametric equation for elliptical orbits is challenging and does not yield a simple analytic form, but there is no consensus on a specific method or solution.

Contextual Notes

The discussion highlights limitations in deriving a time-dependent position formula for elliptical orbits, particularly the reliance on parameters like ##r## and ##\theta## without a clear connection to time.

DuckAmuck
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TL;DR
How to express an eliptical orbit in terms of time
It is fairly trivial to do this with a circular orbit: $$(x,y) = (cos(\omega t),sin(\omega t))$$
where t is time, and $$\omega = \sqrt{GM/r^3}$$
How this parametric equation look for an elliptical orbit?
 
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DuckAmuck said:
Summary:: How to express an eliptical orbit in terms of time

It is fairly trivial to do this with a circular orbit: $$(x,y) = (cos(\omega t),sin(\omega t))$$
where t is time, and $$\omega = \sqrt{GM/r^3}$$
How this parametric equation look for an elliptical orbit?

I don't think it works out very well. Have you tried?
 
Yes. I get something non-analytic.
 
DuckAmuck said:
Yes. I get something non-analytic.
I think that's what you get. The analysis from Newton's laws bails out at a certain point and describes the shape of an orbit in terms of ##r## and ##\theta##, but eliminates ##t##. You get the shape (ellipse) and the period, but not an analytic formula for position as a function of time.
 
Look up "The Kepler Equation". You're in for an interesting ride!
 
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Likes   Reactions: phyzguy, vanhees71 and DuckAmuck
gneill said:
Look up "The Kepler Equation". You're in for an interesting ride!
Thank you!
 

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