Is MgCl2 and NaOH Reaction Endothermic or Exothermic?

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SUMMARY

The reaction between magnesium chloride (MgCl2) and sodium hydroxide (NaOH) involves the formation of magnesium hydroxide (Mg(OH)2) and is analyzed for its thermal properties. The discussion concludes that the reaction is endothermic, as evidenced by the shift in equilibrium towards the reactants when heat is applied, in accordance with Le Chatelier's principle. The addition of energy causes the equilibrium to favor the reactants, confirming the endothermic nature of the reaction.

PREREQUISITES
  • Understanding of chemical equilibrium and Le Chatelier's principle
  • Familiarity with the concepts of endothermic and exothermic reactions
  • Basic knowledge of chemical reactions involving MgCl2 and NaOH
  • Experience with pH indicators, specifically phenolphthalein
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  • Study the principles of Le Chatelier's principle in greater detail
  • Research the thermodynamics of endothermic and exothermic reactions
  • Explore the solubility and precipitation reactions of magnesium compounds
  • Investigate the use of phenolphthalein in acid-base titrations
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Chemistry students, educators, and researchers interested in reaction thermodynamics and chemical equilibrium analysis.

kuahji
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I have the equation Mg(OH)2 (s) -> Mg2+ (aq) + 2 OH- (aq)

I started out with 20 drops of 1.0M MgCl2 in a well & 10 drops of .5M NaOH. Phenolphthalein was also added. When I heated the mixture, it became white, when it cooled it became pink. So, how can I tell if it was endo or exothermic? I want to say it was endothermic because it shifted to the reactant side when heated, but I'm not sure, almost doesn't seem right if you look at the original equation.
 
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It might be helpful to consider energy like a component in the reaction. Let me explain.

An exothermic reaction releases energy to its surroundings. Usually we write this as:

(reactants) <=> (products) delta-H < 0

However, it's often useful to think of it like this:

(reactants) <=> (products) + (energy)

So by Le Chatelier's principle, if you add energy (by heating) to an exothermic reaction, you should shift the equilibrium to the left, i.e. towards the reactant's side. Vice versa for an endothermic reaction, which shifts to the right, i.e., towards the product's side.

Do you now see the answer to your original question?
 
Yes I do, thank for the explanation.
 

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