Energy and collisions when objects stick together, vi, vf help

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SUMMARY

The discussion focuses on calculating initial and final velocities (Vi and Vf) using photogate timing data in a physics lab experiment involving collisions. The user has derived formulas for kinetic energy (KEi and KEf) and momentum (Pi and Pf) based on mass and velocity. Specifically, KEi is calculated as (1/2)(830)Vi², KEf as (1/2)(1160)Vf², Pi as 830Vi, and Pf as 1160Vf. The user seeks clarification on the correct method to calculate Vi and Vf using the photogate times, suggesting a formula involving the diameter of the object and the timing data.

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  • Understanding of basic physics concepts such as momentum and kinetic energy.
  • Familiarity with photogate timing systems and their application in experiments.
  • Proficiency in using Excel for calculations and data analysis.
  • Knowledge of the principles of elastic and inelastic collisions.
NEXT STEPS
  • Learn how to calculate velocity using displacement and time in physics experiments.
  • Research the principles of conservation of momentum in collisions.
  • Explore advanced Excel functions for physics data analysis.
  • Study the differences between elastic and inelastic collisions and their implications on energy and momentum.
USEFUL FOR

Students conducting physics experiments, educators teaching collision dynamics, and anyone interested in applying photogate technology for measuring motion and energy in physical systems.

Jeph
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I'm doing a lab were we used photogates to calculate the time before and after the collision.

I have an initial Photogate Time and a Final Photogate Time..

Working in excel I need to caculate the velocity final and initial using those times. I also need to find KEi KEf Pi and Pf.

I've dervived how to find KEi (1/2(830) vi^2, KEf (1/2(1160)Vf^2), Pi (830*Vi), Pf (1160* Vf)

for when Ma >> Mb

I don't know why I just can't seem to figure how to calculate Vi and Vf using the photogate values. please help!
 
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I think I might have got it..

for Vi.. is it just delta(x) (or the diameter of the cars rod that passes through the photogate) divided by the first time, for initial and the second time for final?
 

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