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Energy available

  1. Jan 22, 2010 #1
    In the formula of available energy of a stationary particle and a moving particle:

    Ea=(square route of)2MtC^2+(MtC^2)^2+(MkC^2)^2

    where:
    Mt= mass of stationary particle
    Mk= kinetic energy of stationary particle
    C= speed of light (299,792,458)

    Can someone tell me what the unit of measurement for the mass of the particle.
    Thanks
     
  2. jcsd
  3. Jan 22, 2010 #2

    mgb_phys

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    Assuming that C is in m/s and E is in Joules = it would be Kg
     
  4. Jan 22, 2010 #3
    This may sound like a stupid question, but why?
     
  5. Jan 22, 2010 #4

    mgb_phys

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    Pretty much from the definition of the Joule

    In CGS you would need mass in g, speed in cm/s and you would get an answer in Ergs.
    But in imperial units you would need a conversion factor for lbs, ft/s and BTU/HP - it's just that for metric systems the definition of the unit of energy makes the factor =1
     
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