Energy needed to inflate approx 0.1m^3 under water

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SUMMARY

The discussion centers on calculating the energy required to inflate a rubber cylinder with a volume of 102,102 cm³ at a depth of 5 cm underwater. The cylinder, measuring 50 cm in diameter and 52 cm in length, experiences pressure due to the surrounding water, which must be overcome during inflation. Participants suggest using an air compressor with an efficiency range of 65% to 85% and emphasize the importance of understanding the average pressure exerted on the cylinder while submerged. The calculation involves considering both the work against water pressure and the energy needed to stretch the rubber material.

PREREQUISITES
  • Understanding of fluid mechanics, specifically pressure calculations (P = ρgh)
  • Knowledge of air compressor efficiency metrics
  • Familiarity with energy storage concepts in pressure vessels
  • Basic principles of thermodynamics related to isothermal processes
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  • Research "Air compressor efficiency calculations" to determine energy requirements
  • Study "Fluid mechanics pressure calculations" for accurate pressure assessments
  • Explore "Isothermal compressed air energy storage" for energy storage methods
  • Investigate "Rubber material properties" to understand energy needed for stretching
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Engineering students, mechanical engineers, and anyone involved in fluid dynamics or energy efficiency in pneumatic systems will benefit from this discussion.

andyg007
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Thread moved from the technical forums, so no Homework Help Template is shown.
How much energy is required to inflate a volume of 102,102cm3 with ambient air at 5cm below the surface of a water tank. The surface of the water tank is 8 meters above sea level.

The object to inflate is a rubber cylinder which has a diameter of 50cm and 52cm in length with 0 resistance from the cylinders material. When fully inflated, I have calculated the surface area of the cylinder to be 12,106cm2.

The temperatures are fixed; the water is 12 degrees and ambient air temperature is 20 degrees Celsius.

The target is to use method of inflation e.g. an air compressor that uses the lowest amount of energy to inflate within 5 minutes.

Any help will be much appreciated.
 
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It will be much the same as that needed to push an already inflated balloon down that far.
What is the purpose here?
 
Thanks for your reply Simon - its a homework question.

My thoughts were the same i.e. an air compressor would require at least the same amount of energy as manually pushing down. I am wanting to understand how efficient air compressors are and try to calculate the amount of energy needed. Any idea how this can be solved?
 
You ask the manufacturer how efficient their air compressors are.
 
Thanks very much for your replies :-)
 
I am a bad engineer but let me give it a try :D
I couldn't understand the question properly but what i assume is that initially the rubber cylinder is flat and immersed in water, if it is immersed horizontally in water the total pressure is P=ro*g*H, now when you inflate the cylinder and keeping the upper surface 5cm below water level, assuming zero resistance from the material you are actually doing work against the pressure developed by the surrounding water, this work would be same as the energy needed for inflation.
this was my understanding of the problem, i am 50 % sure i would be wrong because i am a bad engineer but let's have a discussion lol
 
Hi Ali - your spot on. Btw what does the 'ro' part stand for in the P=ro*g*H?
Thanks for replying :-)
 
ro is the density
sorry i missed it lol
 
  • #10
I agree with Ali's method, if you can calculate the average pressure your balloon will be subject to underwater, and then treating it as stored energy in a pressure vessel could be a useful method. If the balloon is stretching, you will also have to take into account the energy required to stretch the rubber of the balloon as well.

Some information regarding isothermal pressure vessel energy storage can be found here: https://en.wikipedia.org/wiki/Compressed_air_energy_storage#Isothermal_Storage
 
  • #11
Since this is a homework question, let's let the OP do the work from here on... :smile:
andyg007 said:
Thanks for your reply Simon - its a homework question.
 

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