Energy needed to inflate approx 0.1m^3 under water

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Discussion Overview

The discussion revolves around calculating the energy required to inflate a rubber cylinder underwater, specifically at a depth of 5 cm below the surface of a water tank. Participants explore the implications of pressure, efficiency of air compressors, and the physics involved in inflating an object in a fluid environment.

Discussion Character

  • Homework-related
  • Technical explanation
  • Exploratory
  • Debate/contested

Main Points Raised

  • One participant asks for the energy required to inflate a specific volume of air in a rubber cylinder submerged in water, providing dimensions and conditions.
  • Another participant suggests that the energy needed would be similar to that required to push an already inflated balloon down to the same depth.
  • A participant indicates that the energy required for inflation could be related to the efficiency of air compressors, mentioning a range of 65 to 85% efficiency found online.
  • One participant proposes that the work done against the pressure of the surrounding water is equivalent to the energy needed for inflation, expressing uncertainty about their understanding.
  • Another participant agrees with the previous method and suggests calculating the average pressure on the balloon and considering the energy required to stretch the rubber as well.
  • There is a mention of isothermal pressure vessel energy storage as a potentially relevant concept for the problem.

Areas of Agreement / Disagreement

Participants generally agree on the need to consider the pressure exerted by the water and the efficiency of the air compressor, but there is no consensus on the exact method or calculations needed to determine the energy required for inflation.

Contextual Notes

Participants express varying levels of confidence in their understanding of the problem, and there are references to specific calculations and assumptions that may not be fully resolved.

andyg007
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Thread moved from the technical forums, so no Homework Help Template is shown.
How much energy is required to inflate a volume of 102,102cm3 with ambient air at 5cm below the surface of a water tank. The surface of the water tank is 8 meters above sea level.

The object to inflate is a rubber cylinder which has a diameter of 50cm and 52cm in length with 0 resistance from the cylinders material. When fully inflated, I have calculated the surface area of the cylinder to be 12,106cm2.

The temperatures are fixed; the water is 12 degrees and ambient air temperature is 20 degrees Celsius.

The target is to use method of inflation e.g. an air compressor that uses the lowest amount of energy to inflate within 5 minutes.

Any help will be much appreciated.
 
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It will be much the same as that needed to push an already inflated balloon down that far.
What is the purpose here?
 
Thanks for your reply Simon - its a homework question.

My thoughts were the same i.e. an air compressor would require at least the same amount of energy as manually pushing down. I am wanting to understand how efficient air compressors are and try to calculate the amount of energy needed. Any idea how this can be solved?
 
You ask the manufacturer how efficient their air compressors are.
 
Thanks very much for your replies :-)
 
I am a bad engineer but let me give it a try :D
I couldn't understand the question properly but what i assume is that initially the rubber cylinder is flat and immersed in water, if it is immersed horizontally in water the total pressure is P=ro*g*H, now when you inflate the cylinder and keeping the upper surface 5cm below water level, assuming zero resistance from the material you are actually doing work against the pressure developed by the surrounding water, this work would be same as the energy needed for inflation.
this was my understanding of the problem, i am 50 % sure i would be wrong because i am a bad engineer but let's have a discussion lol
 
Hi Ali - your spot on. Btw what does the 'ro' part stand for in the P=ro*g*H?
Thanks for replying :-)
 
ro is the density
sorry i missed it lol
 
  • #10
I agree with Ali's method, if you can calculate the average pressure your balloon will be subject to underwater, and then treating it as stored energy in a pressure vessel could be a useful method. If the balloon is stretching, you will also have to take into account the energy required to stretch the rubber of the balloon as well.

Some information regarding isothermal pressure vessel energy storage can be found here: https://en.wikipedia.org/wiki/Compressed_air_energy_storage#Isothermal_Storage
 
  • #11
Since this is a homework question, let's let the OP do the work from here on... :smile:
andyg007 said:
Thanks for your reply Simon - its a homework question.
 

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